Skip to main content
뒤로

GOB Chemistry Exam 2 Study Guide – Step-by-Step Guidance

스터디 가이드 - 스마트 노트

자료에 맞춘 맞춤형 노트, 핵심 정의, 예시, 맥락을 확장해 제공합니다.

Q1. What is a pure substance, an element, and a mixture?

Background

Topic: Classification of Matter

This question tests your understanding of how matter is categorized in chemistry, including the differences between pure substances, elements, and mixtures.

Key Terms:

  • Pure substance: Matter with a fixed composition and distinct properties.

  • Element: A pure substance made of only one kind of atom.

  • Mixture: A combination of two or more substances where each retains its own properties.

Step-by-Step Guidance

  1. Start by defining what a pure substance is and how it differs from a mixture.

  2. Describe what makes an element unique compared to other pure substances.

  3. Explain what a mixture is and how it can be separated into its components.

  4. Think of examples for each category to help clarify the differences.

Try solving on your own before revealing the answer!

Final Answer:

A pure substance is matter with a fixed composition, such as water or gold. An element is a pure substance consisting of only one type of atom, like oxygen (O2) or copper (Cu). A mixture is a combination of two or more substances, such as air or salt water, where each substance retains its own properties.

Q2. How do solids, liquids, and gases differ?

Background

Topic: States of Matter

This question tests your understanding of the physical properties and behavior of solids, liquids, and gases.

Key Terms:

  • Solid: Definite shape and volume; particles are closely packed.

  • Liquid: Definite volume but no definite shape; particles are less tightly packed than solids.

  • Gas: No definite shape or volume; particles are far apart and move freely.

Step-by-Step Guidance

  1. Describe the arrangement of particles in each state.

  2. Explain how the shape and volume of each state are determined.

  3. Discuss how the movement of particles differs in solids, liquids, and gases.

  4. Consider how compressibility and flow relate to each state.

Try solving on your own before revealing the answer!

Final Answer:

Solids have a definite shape and volume, with particles tightly packed in a fixed arrangement. Liquids have a definite volume but take the shape of their container, with particles able to move past each other. Gases have neither a definite shape nor volume, with particles far apart and moving freely.

Q3. What are physical and chemical changes? Give one example of each.

Background

Topic: Properties of Matter

This question tests your ability to distinguish between physical and chemical changes and to provide examples.

Key Terms:

  • Physical change: A change in form or appearance without altering the chemical composition.

  • Chemical change: A change that results in the formation of new substances.

Step-by-Step Guidance

  1. Define what a physical change is and what happens during such a change.

  2. Define what a chemical change is and how it differs from a physical change.

  3. Think of common examples for each type of change.

  4. Consider how you can tell if a change is physical or chemical (e.g., new substance formed).

Try solving on your own before revealing the answer!

Final Answer:

A physical change alters the form or appearance but not the composition, such as melting ice. A chemical change creates new substances, such as burning wood.

Q4. Explain the difference between a homogeneous and a heterogeneous mixture.

Background

Topic: Types of Mixtures

This question tests your understanding of how mixtures are classified based on their uniformity.

Key Terms:

  • Homogeneous mixture: Uniform composition throughout (e.g., salt water).

  • Heterogeneous mixture: Non-uniform composition (e.g., salad).

Step-by-Step Guidance

  1. Define what makes a mixture homogeneous.

  2. Define what makes a mixture heterogeneous.

  3. Think of examples for each type.

  4. Consider how you can distinguish between the two types visually or by sampling.

Try solving on your own before revealing the answer!

Final Answer:

A homogeneous mixture has a uniform composition throughout, like air or salt water. A heterogeneous mixture has visibly different parts, like a salad or granite.

Q5. What are prefix multipliers? List two examples.

Background

Topic: Units and Measurements

This question tests your knowledge of metric prefixes used to express multiples or fractions of units.

Key Terms:

  • Prefix multiplier: A prefix that indicates a power of ten for a unit (e.g., kilo-, milli-).

Step-by-Step Guidance

  1. Recall common metric prefixes and their meanings.

  2. List two examples, including the prefix, symbol, and value.

  3. Explain how these prefixes are used in measurements.

Try solving on your own before revealing the answer!

Final Answer:

Prefix multipliers are used to indicate multiples or fractions of units. Examples: kilo- (k) means 1,000; milli- (m) means 0.001.

Q6. What is the mass of 2.00 L of an intravenous glucose solution with a density of 1.15 g/mL?

Background

Topic: Density and Mass Calculations

This question tests your ability to use density to calculate mass from volume.

Key Formula:

Step-by-Step Guidance

  1. Identify the given values: volume = 2.00 L, density = 1.15 g/mL.

  2. Convert the volume from liters to milliliters: .

  3. Set up the formula for mass: .

  4. Multiply the density by the converted volume to find the mass.

Try solving on your own before revealing the answer!

Final Answer: 2,300 g

The mass of the solution is 2,300 grams.

Q7. Mercury has a specific gravity of 13.6. How many milliliters of mercury have a mass of 0.35 kg?

Background

Topic: Specific Gravity and Volume Calculations

This question tests your ability to use specific gravity to find the volume of a substance given its mass.

Key Formula:

Step-by-Step Guidance

  1. Convert the mass from kilograms to grams: .

  2. Calculate the density of mercury using its specific gravity: .

  3. Set up the formula for volume: .

  4. Plug in the values to find the volume in milliliters.

Try solving on your own before revealing the answer!

Final Answer: 25.7 mL

350 grams of mercury occupies about 25.7 milliliters.

Q8. The density of a solution is 1.18 g/mL. Its specific gravity is

Background

Topic: Density and Specific Gravity

This question tests your understanding of how to calculate specific gravity from density.

Key Formula:

Step-by-Step Guidance

  1. Identify the density of the solution: 1.18 g/mL.

  2. Recall the density of water: 1.00 g/mL.

  3. Set up the formula for specific gravity.

  4. Divide the density of the solution by the density of water.

Try solving on your own before revealing the answer!

Final Answer: 1.18

The specific gravity is 1.18.

Q9. A clinic had 30 patients on Friday morning. If 24 patients were given flu shots, what percentage of the patients received flu shots?

Background

Topic: Percent Calculations

This question tests your ability to calculate percentages from given numbers.

Key Formula:

Step-by-Step Guidance

  1. Identify the total number of patients (whole) and the number who received flu shots (part).

  2. Set up the formula for percent.

  3. Plug in the values: part = 24, whole = 30.

  4. Multiply the result by 100 to get the percentage.

Try solving on your own before revealing the answer!

Final Answer: 80%

80% of the patients received flu shots.

Q10. An alloy contains 57 g of pure silver and 23 g of pure copper. What is the percentage of silver in the alloy?

Background

Topic: Percent Composition

This question tests your ability to calculate the percent composition of a component in a mixture.

Key Formula:

Step-by-Step Guidance

  1. Find the total mass of the alloy by adding the masses of silver and copper.

  2. Set up the formula for percent composition.

  3. Plug in the mass of silver and the total mass.

  4. Multiply by 100 to get the percentage.

Try solving on your own before revealing the answer!

Final Answer: 71.3%

Silver makes up 71.3% of the alloy by mass.

Q11. A collection of coins contains 9 nickels, 6 quarters, and 5 dimes. What is the percentage of dimes in the collection?

Background

Topic: Percent Calculations

This question tests your ability to calculate the percentage of a subset in a collection.

Key Formula:

Step-by-Step Guidance

  1. Find the total number of coins by adding nickels, quarters, and dimes.

  2. Set up the formula for percent.

  3. Plug in the number of dimes and the total number of coins.

  4. Multiply by 100 to get the percentage.

Try solving on your own before revealing the answer!

Final Answer: 23.8%

There are 25% dimes in the collection.

Q12. A saline solution has a mass of 24 g, of which 2.8 g is sodium chloride. What percent of the solution is sodium chloride?

Background

Topic: Percent Composition

This question tests your ability to calculate the percent composition of a solute in a solution.

Key Formula:

Step-by-Step Guidance

  1. Identify the mass of sodium chloride (solute) and the total mass of the solution.

  2. Set up the formula for percent composition.

  3. Plug in the values and multiply by 100.

Try solving on your own before revealing the answer!

Final Answer: 11.7%

11.7% of the solution is sodium chloride by mass.

Q13. What is energy? What is work? List some examples of each.

Background

Topic: Energy and Work

This question tests your understanding of the concepts of energy and work in chemistry.

Key Terms:

  • Energy: The capacity to do work or produce heat.

  • Work: The process of causing movement against a force.

Step-by-Step Guidance

  1. Define energy and work in your own words.

  2. Think of examples of energy (e.g., heat, light, chemical energy).

  3. Think of examples of work (e.g., lifting an object, moving a piston).

  4. Explain how energy and work are related.

Try solving on your own before revealing the answer!

Final Answer:

Energy is the capacity to do work or produce heat, such as electrical energy or chemical energy. Work is the movement of an object against a force, like lifting a book or compressing a spring.

Q14. What is kinetic energy? What is potential energy? List some examples of each.

Background

Topic: Types of Energy

This question tests your understanding of kinetic and potential energy and their examples.

Key Terms:

  • Kinetic energy: Energy due to motion.

  • Potential energy: Energy stored due to position or arrangement.

Step-by-Step Guidance

  1. Define kinetic energy and potential energy.

  2. Think of examples of kinetic energy (e.g., moving car, flowing water).

  3. Think of examples of potential energy (e.g., stretched spring, chemical bonds).

  4. Explain how energy can be converted between these forms.

Try solving on your own before revealing the answer!

Final Answer:

Kinetic energy is energy of motion, like a moving ball or a flowing river. Potential energy is stored energy, like a stretched rubber band or a battery.

Q15. What is the SI unit of energy? List some other common units of energy.

Background

Topic: Units of Energy

This question tests your knowledge of the units used to measure energy.

Key Terms:

  • SI unit of energy: Joule (J)

  • Other units: calorie (cal), kilowatt-hour (kWh)

Step-by-Step Guidance

  1. Recall the SI unit for energy.

  2. List other common units and their relationships to the SI unit.

  3. Explain where these units are commonly used.

Try solving on your own before revealing the answer!

Final Answer:

The SI unit of energy is the joule (J). Other common units include the calorie (cal) and kilowatt-hour (kWh).

Q16. What is heat capacity?

Background

Topic: Heat and Temperature

This question tests your understanding of the concept of heat capacity.

Key Terms:

  • Heat capacity: The amount of heat required to raise the temperature of an object by 1 degree Celsius.

Step-by-Step Guidance

  1. Define heat capacity in your own words.

  2. Explain how heat capacity differs from specific heat capacity.

  3. Think of examples of substances with high and low heat capacities.

Try solving on your own before revealing the answer!

Final Answer:

Heat capacity is the amount of heat needed to raise the temperature of an object by 1°C. It depends on the object's mass and material.

Q17. Suppose you find a penny (minted before 1982, when pennies were almost entirely copper) in the snow. How much heat is absorbed by the penny as it warms from the temperature of the snow, which is -8.0 ºC, to the temperature of your body, 37.0 ºC? Assume the penny is pure copper and has a mass of 3.10 g.

Background

Topic: Heat Transfer and Specific Heat

This question tests your ability to calculate the heat absorbed using specific heat capacity.

Key Formula:

Where:

  • = heat absorbed (J)

  • = mass (g)

  • = specific heat capacity (J/g°C)

  • = change in temperature (°C)

Step-by-Step Guidance

  1. Identify the mass of the penny ( g), the initial temperature ( °C), and the final temperature ( °C).

  2. Find the specific heat capacity of copper ( J/g°C).

  3. Calculate the change in temperature: .

  4. Set up the formula: .

  5. Multiply the values to find the heat absorbed.

Try solving on your own before revealing the answer!

Final Answer: 53.6 J

J

The penny absorbs 53.6 joules of heat.

Q18. A 32.5 g cube of aluminum initially at 45.8 ºC is submerged into 105.3 g of water at 15.4 ºC. What is the final temperature of both substances at thermal equilibrium? (Assume that the aluminum and the water are thermally isolated from everything else.)

Background

Topic: Heat Transfer and Thermal Equilibrium

This question tests your ability to use heat transfer equations to find the final temperature at equilibrium.

Key Formula:

Where:

  • = mass (g)

  • = specific heat capacity (J/g°C)

  • = final temperature (°C)

  • = initial temperature (°C)

Step-by-Step Guidance

  1. Write the heat lost by aluminum: .

  2. Write the heat gained by water: .

  3. Set up the equation: .

  4. Plug in the masses, specific heat capacities ( J/g°C, J/g°C), and initial temperatures.

  5. Solve for algebraically.

Try solving on your own before revealing the answer!

Final Answer: 16.7 ºC

The final temperature at equilibrium is 16.7°C.

This is found by solving the equation for using the masses, specific heat capacities, and initial temperatures.

Q19. To determine whether a shiny gold-colored rock is actually gold, a chemistry student decides to measure its heat capacity. She first weighs the rock and finds it has a mass of 4.7 g. She then finds that upon absorption of 57.2 J of heat, the temperature of the rock rises from 25 ºC to 57 ºC. Find the specific heat capacity of the substance composing the rock and determine whether the value is consistent with the rock being pure gold.

Background

Topic: Specific Heat Capacity

This question tests your ability to calculate specific heat capacity and compare it to known values.

Key Formula:

Where:

  • = specific heat capacity (J/g°C)

  • = heat absorbed (J)

  • = mass (g)

  • = change in temperature (°C)

Step-by-Step Guidance

  1. Identify the mass ( g), heat absorbed ( J), and temperature change ().

  2. Set up the formula for specific heat capacity: .

  3. Plug in the values and calculate .

  4. Compare the calculated value to the specific heat capacity of gold (0.128 J/g°C).

Try solving on your own before revealing the answer!

Final Answer: 0.26 J/g°C (not gold)

J/g°C

This value is higher than the specific heat capacity of gold (0.128 J/g°C), so the rock is not pure gold.

Q20. A 55.0 g aluminum block initially at 27.5 ºC absorbs 725 J of heat. What is the final temperature of the aluminum?

Background

Topic: Heat Transfer and Specific Heat

This question tests your ability to calculate the final temperature after heat absorption.

Key Formula:

Where:

  • = heat absorbed (J)

  • = mass (g)

  • = specific heat capacity (J/g°C)

  • = initial temperature (°C)

  • = final temperature (°C)

Step-by-Step Guidance

  1. Identify the mass ( g), heat absorbed ( J), and initial temperature ( °C).

  2. Find the specific heat capacity of aluminum ( J/g°C).

  3. Set up the formula: .

  4. Rearrange the formula to solve for .

  5. Plug in the values and calculate .

Try solving on your own before revealing the answer!

Final Answer: 41.1 ºC

°C

The final temperature of the aluminum block is 41.1°C.

Pearson Logo

스터디 프렙