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Ch. 15 - Conjugated Systems, Orbital Symmetry, and Ultraviolet Spectroscopy
Wade - Organic Chemistry 9th Edition
Wade9th EditionOrganic ChemistryISBN: 9780135213728당신이 사용하는 게 아니라요?교과서 변경
15장, 문제 37g

The pentadienyl radical, H2C=CH–CH=CH–CH2•, has its unpaired electron delocalized over three carbon atoms.
g. Remove the highest-energy electron from the pentadienyl radical to give the pentadienyl cation. Which carbon atoms share the positive charge? Does this picture agree with the resonance picture?

검증된 단계별 안내
1
Step 1: Understand the structure of the pentadienyl radical. It consists of a conjugated system with alternating double and single bonds: H₂C=CH-CH=CH-CH₂·. The unpaired electron is delocalized over the three central carbon atoms (C2, C3, and C4) due to resonance.
Step 2: Removing the highest-energy electron from the pentadienyl radical results in the formation of the pentadienyl cation. This means the unpaired electron is removed, leaving a positive charge that will also be delocalized over the conjugated system.
Step 3: Draw the resonance structures of the pentadienyl cation. The positive charge will be shared among the three central carbon atoms (C2, C3, and C4) due to the delocalization of π-electrons in the conjugated system. Use curved arrows to show the movement of electrons in each resonance structure.
Step 4: Analyze the resonance structures to confirm that the positive charge is distributed over C2, C3, and C4. This delocalization stabilizes the cation and agrees with the resonance picture of the pentadienyl radical, where the unpaired electron was also delocalized over the same three carbon atoms.
Step 5: Conclude that the positive charge in the pentadienyl cation is shared among C2, C3, and C4, and this distribution is consistent with the resonance picture of the original pentadienyl radical. This demonstrates the importance of resonance in stabilizing both radicals and cations in conjugated systems.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
14m

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Radicals and Cations

Radicals are species that contain an unpaired electron, making them highly reactive. In contrast, cations are positively charged species formed when an electron is removed from a neutral atom or molecule. In the case of the pentadienyl radical, removing the highest-energy electron results in a pentadienyl cation, which has a positive charge that can be delocalized over adjacent carbon atoms.
추천 영상:
가이드 코스
0:52
Cationic Polymerization Concept 3

Delocalization of Charge

Delocalization refers to the spreading of electrons or charge over multiple atoms rather than being localized on a single atom. In the pentadienyl cation, the positive charge can be shared among the carbon atoms involved in the double bonds, which stabilizes the cation. This delocalization is a key factor in understanding the stability and reactivity of the cation.
추천 영상:
01:34
Calculating formal and net charge.

Resonance Structures

Resonance structures are different ways of drawing a molecule that represent the same arrangement of atoms but differ in the placement of electrons. For the pentadienyl cation, resonance structures illustrate how the positive charge can be distributed across different carbon atoms. This concept helps explain the stability of the cation, as the actual structure is a hybrid of these resonance forms.
추천 영상:
03:04
Drawing Resonance Structures
관련 실천
교과서 질문

The pentadienyl radical, H2C=CH–CH=CH–CH2•, has its unpaired electron delocalized over three carbon atoms.

h. Add an electron to the pentadienyl radical to give the pentadienyl anion. Which carbon atoms share the negative charge? Does this picture agree with the resonance picture?

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교과서 질문

A student was studying terpene synthesis, and she wanted to make the compound shown here. First she converted 3-bromo-6-methylcyclohexene to alcohol A. She heated alcohol A with sulfuric acid and purified one of the components (compound B) from the resulting mixture. Compound B has the correct molecular formula for the desired product.

a. Suggest how 3-bromo-6-methylcyclohexene might be converted to alcohol A.

530
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교과서 질문

The pentadienyl radical, H2C=CH–CH=CH–CH2•, has its unpaired electron delocalized over three carbon atoms.

b. How many MOs are there in the molecular orbital picture of the pentadienyl radical?

c. How many nodes are there in the lowest-energy MO of the pentadienyl system? How many in the highest-energy MO?

d. Draw the MOs of the pentadienyl system in order of increasing energy

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교과서 질문

A student was studying terpene synthesis, and she wanted to make the compound shown here. First she converted 3-bromo-6-methylcyclohexene to alcohol A. She heated alcohol A with sulfuric acid and purified one of the components (compound B) from the resulting mixture. Compound B has the correct molecular formula for the desired product.

(c) Propose a mechanism for the dehydration of alcohol A to compound B.

1469
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교과서 질문

The pentadienyl radical, H2C=CH–CH=CH–CH2•, has its unpaired electron delocalized over three carbon atoms.

f. Show how your molecular orbital picture agrees with the resonance picture showing delocalization of the unpaired electron onto three carbon atoms.

955
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교과서 질문

The pentadienyl radical, H2C=CH–CH=CH–CH2•, has its unpaired electron delocalized over three carbon atoms.

a. Use resonance forms to show which three carbon atoms bear the unpaired electron.

823
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