Beginning Algebra
3(x+1)x\(\displaystyle\) \(\frac{3(x + 1)}{x}\)
x+1x\(\displaystyle\) \(\frac{x + 1}{x}\)
3(x−1)x\(\displaystyle\) \(\frac{3(x - 1)}{x}\)
3(x+1)2x{\(\displaystyle\]\frac{3(x+1)}{2x}\)}