Find both intercepts for the equation $-3x+6y=12$.

$x$-intercept: $(-4,0)$

$y$-intercept: $(0,2)$

$x$-intercept: $(0,-4)$

$y$-intercept: $(2,0)$

$x$-intercept: $(4,0)$

$y$-intercept: $(0,-2)$

$x$-intercept: $(-4,2)$

$y$-intercept: $(0,12)$