If $y$ varies inversely as $x$ and $y=6$ when $x=2$, find the inverse variation equation and then compute $y$ when $x=3$.

$y=\frac{12}{x}$

$y\left(3\right)=4$

$y=3x$

$y\left(3\right)=9$

$y=12x$

$y\left(3\right)=36$

$y=\frac{3}{x}$

$y\left(3\right)=1$