Beginning Algebra
abn=a1nb1n+1\(\sqrt\)[n]{\(\frac{a}{b}\)}=\(\frac{a^{\frac{1}{n}\)}}{b^{\(\frac{1}{n+1}\)}}
abn=an⋅bn\(\sqrt\)[n]{\(\frac{a}{b}\)}=\(\sqrt\)[n]{a}\(\cdot\]\sqrt\)[n]{b}
abn=anbn\(\sqrt\)[n]{\(\frac{a}{b}\)}=\(\frac{\sqrt[n]{a}\)}{\(\sqrt\)[n]{b}}
abn=an−bn\(\sqrt\)[n]{\(\frac{a}{b}\)}=\(\sqrt\)[n]{a}-\(\sqrt\)[n]{b}