to-one-function-defined-by-ordered-pairs-30122547-which-ordered-pairs-define-f-1

Question

Let ff be the one-to-one function defined by ordered pairs {(−3,0),(−1,2),(2,5),(4,7)}\left\lbrace{(-3,0),(-1,2),(2,5),(4,7)}\right\rbrace. Which ordered pairs define f−$$1f^{-1}$$?

Accepted Answer

{(0,−3),(2,−1),(5,2),(7,4)}\left\lbrace{(0,-3),(2,-1),(5,2),(7,4)}\right\rbrace

Answer

{(−3,0),(2,−1),(5,2),(7,4)}\left\lbrace{(-3,0),(2,-1),(5,2),(7,4)}\right\rbrace

Answer

{(−3,0),(−1,2),(2,5),(4,7)}\left\lbrace{(-3,0),(-1,2),(2,5),(4,7)}\right\rbrace

Answer

{(0,3),(−2,1),(−5,2),(−7,4)}\left\lbrace{(0,3),(-2,1),(-5,2),(-7,4)}\right\rbrace

Let ff be the one-to-one function defined by ordered pairs {(−3,0),(−1,2),(2,5),(4,7)}\(\left\]\lbrace{(-3,0),(-1,2),(2,5),(4,7)}\[\right\]\rbrace\). Which ordered pairs define f−1f^{-1}?

Let $f$ be the one-to-one function defined by ordered pairs ${(- 3, 0), (- 1, 2), (2, 5), (4, 7)}$ . Which ordered pairs define $f^{- 1}$ ?