Beginning & Intermediate Algebra
(f∘g)(x)=1+xx(f\(\circ\) g)(x)=\(\frac{1+x}{x}\), (g∘f)(x)=1x+1(g\(\circ\) f)(x)=\(\frac{1}{x+1}\), and they are not equal
(f∘g)(x)=1+xx(f\(\circ\) g)(x)=\(\frac{1+x}{x}\), (g∘f)(x)=1x+1(g\(\circ\) f)(x)=\(\frac{1}{x+1}\), and they are equal
(f∘g)(x)=x+1(f∘g)(x) = x + 1, (g∘f)(x)=1x(g\(\circ\) f)(x)=\(\frac{1}{x}\), and they are not equal
(f∘g)(x)=1x+1(f\(\circ\) g)(x)=\(\frac{1}{x+1}\), (g∘f)(x)=1+xx(g\(\circ\) f)(x)=\(\frac{1+x}{x}\), and they are equal