the-center-and-radius-show-detailed-completion-steps-for-fractional-coefficients

Question

Convert x2+y2+13x−52y−1=$$0x^2$+y^2$$+\frac13x-\frac52y-1=0 into standard form.

Accepted Answer

(x+16)2+(y−54)2=373144\left(x+\frac16\$$right)^2$$+\left(y-\frac54\$$right)^2$$=\frac{373}{144}

Answer

(x+16)2+(y−54)2=37312\left(x+\frac16\$$right)^2$$+\left(y-\frac54\$$right)^2$$=\frac{373}{12}

Answer

(x−16)2+(y+54)2=373144\left(x-\frac16\$$right)^2$$+\left(y+\frac54\$$right)^2$$=\frac{373}{144}

Answer

(x+16)2+(y−54)2=1\left(x+\frac16\$$right)^2$$+\left(y-\frac54\$$right)^2=1$$

Convert x2+y2+13x−52y−1=0x^2+y^2+\(\frac\)13x-\(\frac\)52y-1=0 into standard form.