Beginning & Intermediate Algebra
x0.06+y0.14=100.09\(\frac{x}{0.06}\)+\(\frac{y}{0.14}\)=\(\frac{10}{0.09}\) and x+y=10x+y=10
0.6x+1.4y=0.9⋅100.6x+1.4y=0.9\(\cdot\)10 and x−y=10x-y=10
0.06x+0.14y=0.09⋅100.06x+0.14y=0.09\(\cdot\)10 and x+y=10x+y=10
6x+14y=96x+14y=9 and x+y=10x+y=10