Question

An artificial 'cell' consisting of an aqueous solution enclosed in a selectively permeable membrane is immersed in a beaker containing a different solution, the 'environment,' as shown in the accompanying diagram. The membrane is permeable to water and to the simple sugars glucose and fructose but impermeable to the disaccharide sucrose.

a. Draw solid arrows to indicate the net movement of solutes into and/or out of the cell.
b. Is the solution outside the cell isotonic, hypotonic, or hypertonic?
c. Draw a dashed arrow to show the net osmosis, if any.
d. Will the artificial cell become more flaccid, more turgid, or stay the same?
e. Eventually, will the two solutions have the same or different solute concentrations?

Accepted Answer

Examine the diagram to identify the solutes present inside and outside the artificial cell. Note that the membrane is permeable to water, glucose, and fructose, but not to sucrose. Determine the concentration gradient for each permeable solute (glucose and fructose) across the membrane. Solutes will move from areas of higher concentration to areas of lower concentration. Draw solid arrows on the diagram to indicate the net movement of glucose and fructose based on their concentration gradients. If glucose is more concentrated inside the cell, draw an arrow pointing outwards, and vice versa for fructose. Assess the tonicity of the solution outside the cell by comparing the total solute concentration inside and outside the cell. If the external solution has a higher solute concentration, it is hypertonic; if lower, hypotonic; if equal, isotonic. Draw a dashed arrow to represent the net movement of water (osmosis) based on the tonicity assessment. Water will move towards the area with higher solute concentration. Determine if the cell will become more flaccid (losing water), more turgid (gaining water), or stay the same, and predict whether the solute concentrations will eventually equalize.

비슷한 문제에 대한 검증된 영상 답변:

주요 개념

Selective Permeability

Osmosis

Tonicity