find-the-derivative-of-ycosx2sinxyfraccos-x2-sin-x

Question

Find the derivative of y=cos⁡x2−sin⁡xy=\frac{\cos x}{2-\sin x}.

Accepted Answer

y′=1−2sin⁡x(2−sin⁡$$x)2y^{\prime}$$=\frac{1-2\sin x}{\left(2-\sin x\$$right)^2$$}

Answer

y′=2cos⁡x(2−sin⁡$$x)2y^{\prime}$$=\frac{2\cos x}{\left(2-\sin x\$$right)^2$$}

Answer

y′=−sin⁡x(2−sin⁡$$x)2y^{\prime}$$=-\frac{\sin x}{\left(2-\sin x\$$right)^2$$}

Answer

y′=−cos⁡x(2−sin⁡$$x)2y^{\prime}$$=-\frac{\cos x}{\left(2-\sin x\$$right)^2$$}

Find the derivative of y=cosx2−sinxy=\(\frac{\cos x}{2-\sin x}\).