a-damped-harmonic-oscillators-displacement-from-equilibrium-is-described-by-the-

Question

A damped harmonic oscillator's displacement from equilibrium is described by the equation x(t)=4e−0.5tcos⁡(4t)x(t)=$$4e^{-0.5t}$$\cos(4t), where tt is time in seconds. Find the first time at which the oscillator's displacement is at a maximum.

Accepted Answer

t=0.754 secondst=0.754	ext{ seconds}

Answer

t=2.754 secondst=2.754	ext{ seconds}

Answer

t=1.754 secondst=1.754	ext{ seconds}

Answer

t=0.457 secondst=0.457	ext{ seconds}

A damped harmonic oscillator's displacement from equilibrium is described by the equation x(t)=4e−0.5tcos(4t)x(t)=4e^{-0.5t}\(\cos\)(4t), where tt is time in seconds. Find the first time at which the oscillator's displacement is at a maximum.

A damped harmonic oscillator's displacement from equilibrium is described by the equation $x (t) = 4 e^{- 0.5 t} \cos (4 t)$ , where $t$ is time in seconds. Find the first time at which the oscillator's displacement is at a maximum.