solve-the-initial-value-problem-xt3e2t-xt-3e2t-x05-x0-5-what-is-xt-xt

Question

Solve the initial value problem: x′(t)=$$3e2tx^{\prime}(t$$)=$$3e^{2t}$$, x(0)=5 x(0) = 5 .

Accepted Answer

x(t)=3e2t+72x\left(t\right)=\frac{$$3e^{2t}+7$$}{2}

Answer

x(t)=3e2t+2x(t)=$$3e^{2t}+2$$

Answer

x(t)=3e2t−72x\left(t\right)=\frac{$$3e^{2t}-7$$}{2}

Answer

x(t)=3e2t+52x\left(t\right)=\frac{$$3e^{2t}+5$$}{2}

Solve the initial value problem: x′(t)=3e2tx^{\(\prime\)}(t)=3e^{2t}, x(0)=5 x(0) = 5 .