calculate-the-volume-of-the-solid-formed-by-revolving-the-region-bounded-by-ysin

Question

Calculate the volume of the solid formed by revolving the region bounded by y=sin⁡(x)cos⁡12(x)y=\sin(x)\$$cos^{\frac12}(x) $$and the xx-axis over [0,π2][0,\frac{\pi}{2}] about the xx-axis.

Accepted Answer

π3 cubic units\frac{\pi}{3}	ext{ cubic units}

Answer

π27 cubic units\frac{\pi}{27}	ext{ cubic units}

Answer

π9 cubic units\frac{\pi}{9}	ext{ cubic units}

Answer

4π3 cubic units\frac{4\pi}{3}	ext{ cubic units}

Calculate the volume of the solid formed by revolving the region bounded by y=sin(x)cos12(x)y=\(\sin\)(x)\(\cos\)^{\(\frac\)12}(x) and the xx-axis over [0,π2][0,\(\frac{\pi}{2}\)] about the xx-axis.

Calculate the volume of the solid formed by revolving the region bounded by $y = \sin (x) \cos^{\frac{1}{2}} (x)$ and the $x$ -axis over $open bracket 0 comma pi over 2 close bracket$ about the $x$ -axis.