Business Calculus
V′(10)=4 V'(10) = 4 V′(10)=4 m3/s\(\text{ m}\)^3\(\text{/s}\) m3/s
The rate of change of the volume of the balloon is 4 m3/s4\(\text{ m}\)^3\(\text{/s}\)4 m3/s at t=10 t = 10 t=10 s\(\text{ s}\) s.
V′(10)=10V^{\(\prime\)}\(\left\)(10\(\right\))=10 m3/s\(\text{ m}\)^3\(\text{/s}\) m3/s
The rate of change of the volume of the balloon is 1010 m3/s\(\text{ m}\)^3\(\text{/s}\) m3/s at t=10 t = 10 t=10 s\(\text{ s}\) s.
V′(10)=40V^{\(\prime\)}\(\left\)(10\(\right\))=40 m3/s\(\text{ m}\)^3\(\text{/s}\) m3/s
The rate of change of the volume of the balloon is 4040 m3/s\(\text{ m}\)^3\(\text{/s}\) m3/s at t=10 t = 10 t=10 s\(\text{ s}\) s.
V′(10)=5V^{\(\prime\)}\(\left\)(10\(\right\))=5 m3/s\(\text{ m}\)^3\(\text{/s}\) m3/s
The rate of change of the volume of the balloon is 55 m3/s\(\text{ m}\)^3\(\text{/s}\) m3/s at t=10 t = 10 t=10 s\(\text{ s}\) s.