in-a-wilcoxon-signed-ranks-test-suppose-you-have-nn-nonzero-paired-differences-a

Question

In a Wilcoxon Signed-Ranks Test, suppose you have nn nonzero paired differences and the sum of the negative ranks is tt. What is the expression for the sum of the positive ranks in terms of nn and tt?

Accepted Answer

﻿n(n+1)2−t\frac{n\left(n+1\right)}{2}-t2n(n+1)​−t﻿

Answer

n(n−1)4+t\frac{n\left(n-1\right)}{4}+t

Answer

n(n−1)4−t\frac{n\left(n-1\right)}{4}-t

Answer

n(n+1)2+t\frac{n\left(n+1\right)}{2}+t