Calculus
−ln∣1−tan(x2)∣+C-\(\ln\)\(\left\)|1-\(\tan\[\left\)(\(\frac{x}{2}\]\right\))\(\right\)|+C
−ln∣1+tan(x2)∣+C-\(\ln\)\(\left\)|1+\(\tan\[\left\)(\(\frac{x}{2}\]\right\))\(\right\)|+C
ln∣1−tan(x2)∣+C\(\ln\)\(\left\)|1-\(\tan\[\left\)(\(\frac{x}{2}\]\right\))\(\right\)|+C
−ln∣1−cos(x2)∣+C-\(\ln\)\(\left\)|1-\(\cos\[\left\)(\(\frac{x}{2}\]\right\))\(\right\)|+C