evaluate-the-integral-1x2x24-dx-int-frac1x2x2-4-dx

Question

Evaluate the integral: ∫1x2(x2+4) dx \int \frac{1}{$$x^2$(x^2 + 4$$)} \, dx

Accepted Answer

−14x−18tan⁡−1(x2)+C-\frac{1}{4x}-\frac{1}{8}\$$tan^{-1}$$\left(\frac{x}{2}\right)+C

Answer

−18x+14tan⁡−1(x2)+C-\frac{1}{8x}+\frac14\$$tan^{-1}$$\left(\frac{x}{2}\right)+C

Answer

18x−18tan⁡−1(x4)+C\frac{1}{8x}-\frac{1}{8}\$$tan^{-1}$$\left(\frac{x}{4}\right)+C

Answer

−14x+116tan⁡−1(x4)+C-\frac{1}{4x}+\frac{1}{16}\$$tan^{-1}$$\left(\frac{x}{4}\right)+C

Evaluate the integral: ∫1x2(x2+4)dx \(\int\) \(\frac{1}{x^2(x^2 + 4)}\) \, dx