to-determine-the-convergence-of-m13m6m4-displaystylesumm1infty-frac3m6m-4-which-

Question

To determine the convergence of ∑m=1∞3m6m+4 \displaystyle\sum_{m=1}^{\infty} \frac{3^m}{6^m + 4} , which comparison series should you use with the Comparison Test?

Accepted Answer

∑m=1∞(12)m \displaystyle\sum_{m=1}^{\infty}\left(\frac12\$$right)^{m}$$

Answer

∑m=1∞(13)m{\displaystyle\sum_{m=1}^{\infty}\left(\frac13\$$right)^{m}$$}

Answer

∑m=1∞(32)m{\displaystyle\sum_{m=1}^{\infty}\left(\frac32\$$right)^{m}$$}

Answer

∑m=1∞(23)m{\displaystyle\sum_{m=1}^{\infty}\left(\frac23\$$right)^{m}$$}

To determine the convergence of ∑m=1∞3m6m+4 \(\displaystyle\)\(\sum\)_{m=1}^{\(\infty\)} \(\frac{3^m}{6^m + 4}\) , which comparison series should you use with the Comparison Test?

To determine the convergence of $\sum_{m = 1}^{\infty} \frac{3^{m}}{6^{m} + 4}$ , which comparison series should you use with the Comparison Test?