given-the-velocity-function-vt-3t-5-and-the-initial-position-s0-2-find-the-posit

Question

Consider the velocity function v(t)=3t−5 v(t) = 3t - 5 . If the initial position s(0)=2 s(0) = 2 , determine the position function s(t) s(t) .

Accepted Answer

32t2−5t+2\$$frac32t^2-5t+2$$

Answer

$$t2+3t+2t^2 + 3t + 2$$

Answer

32t2−5t\$$frac32t^2-5t$$

Answer

t2−$$5t+2t^2 - 5t + 2$$