evaluate-the-integral-e4tcos3t-dt-displaystyleint-e4t-cos3t-dt

Question

Evaluate ∫e4tcos⁡(3t) dt \displaystyle\int $$e^{4t}$$ \cos(3t) \, dt  using a standard integral found in a table of integrals.

Accepted Answer

e4t25(4cos⁡(3t)+3sin⁡(3t))+C\displaystyle\frac{$$e^{4t}$$}{25}\left(4\cos(3t)+3\sin(3t)\right)+C

Answer

e4t25(3cos⁡(3t)+4sin⁡(3t))+C{\displaystyle\frac{$$e^{4t}$$}{25}\left(3\cos(3t)+4\sin(3t)\right)+C}

Answer

e4t7(4cos⁡(3t)+3sin⁡(3t))+C{\displaystyle\frac{$$e^{4t}$$}{7}\left(4\cos(3t)+3\sin(3t)\right)+C}

Answer

e7t25(4cos⁡(3t)+3sin⁡(3t))+C{\displaystyle\frac{$$e^{7t}$$}{25}\left(4\cos(3t)+3\sin(3t)\right)+C}

Evaluate ∫e4tcos(3t)dt \(\displaystyle\]\int\) e^{4t} \(\cos\)(3t) \, dt using a standard integral found in a table of integrals.