a-function-fx-sqrtx-is-revolved-around-the-x-axis-from-x-0-to-x-4-what-is-the-in

Question

A function f(x) = sqrt(x) is revolved around the x-axis from x = 0 to x = 4. What is the integral setup to find the volume of the resulting solid of revolution?

Accepted Answer

∫ from 0 to 4 of π$$(sqrt(x))^2 dx$$

Answer

∫ from 0 to 4 of π$$x^2 dx$$

Answer

∫ from 0 to 4 of πx dx

Answer

∫ from 0 to 4 of π(sqrt(x)) dx