a-diver-jumps-off-a-diving-board-10-feet-above-the-pool-with-an-initial-upward-v

Question

A diver jumps off a diving board 1010 feet above the pool with an initial upward velocity of 16 ft/s16	ext{ ft/s}. The height (in feet) of the diver above the water tt seconds after the jump is given by s(t)=−16t2+16t+10s(t)=$$-16t^2+16t+10. $$What is the maximum height of the diver above the water?

Accepted Answer

14 ft14	ext{  ft}

Answer

24 ft24	ext{  ft}

Answer

16 ft16	ext{  ft}

Answer

10 ft10	ext{  ft}