set-up-the-partial-fraction-decomposition-for-5x27x26x9x22x5-frac5x2-7x2-6x-9x2-

Question

Set up the partial fraction decomposition for 5x2+7(x2−6x+9)(x2+2x+5) \frac{$$5x^2 + 7$$}{$$(x^2 - 6x$$ + $$9)(x^2 + 2x + 5$$)} . Do not solve for the unknown constants.

Accepted Answer

Ax−3+B(x−3)2+Cx+Dx2+2x+5\frac{A}{x - 3}+\frac{B}{(x - $$3)^2$$}+\frac{Cx + D}{$$x^2 + 2x + 5$$}

Answer

Ax−3+Bx2+2x+5+Cx+D(x−3)2\frac{A}{x - 3}+\frac{B}{$$x^2+2x+5$$}+\frac{Cx+D}{\left(x-3\$$right)^2$$}

Answer

Ax−3+B(x−3)2+Cx2+2x+5\frac{A}{x - 3}+\frac{B}{(x - $$3)^2$$}+\frac{C}{$$x^2+2x+5$$}

Answer

Ax+B(x−3)2+Cx+Dx2+2x+5\frac{Ax+B}{$$(x-3)^2$$}+\frac{Cx + D}{$$x^2 + 2x + 5$$}

Set up the partial fraction decomposition for 5x2+7(x2−6x+9)(x2+2x+5) \(\frac{5x^2 + 7}{(x^2 - 6x + 9)(x^2 + 2x + 5)}\) . Do not solve for the unknown constants.

Set up the partial fraction decomposition for $\frac{5 x^{2} + 7}{(x^{2} - 6 x + 9) (x^{2} + 2 x + 5)}$ . Do not solve for the unknown constants.