consider-the-sequence-given-by-cn-frac2n2-5n-3-sinn7n3-n-using-the-squeeze-theor

Question

Consider the sequence given by cn=(2n2+5n−3)sin⁡n7n3−nc_{n}=\frac{$$(2n^2+5n-3$$)\sin n}{$$7n^3-n$$}. Using the Squeeze Theorem, determine lim⁡n→∞cn \displaystyle \lim_{n 	o \infty} c_n .

Accepted Answer

00

Answer

11

Answer

−1-1

Answer

∞\infty

Consider the sequence given by cn=(2n2+5n−3)sinn7n3−nc_{n}=\(\frac{(2n^2+5n-3)\sin n}{7n^3-n}\). Using the Squeeze Theorem, determine limn→∞cn \(\displaystyle\) \(\lim\)_{n \(\to\) \(\infty\)} c_n .

Consider the sequence given by $c_{n} = \frac{(2 n^{2} + 5 n - 3) \sin n}{7 n^{3} - n}$ . Using the Squeeze Theorem, determine $\lim_{n \to \infty} c_{n}$ .