use-a-shift-to-explain-how-the-graph-of-hxx26x27hxsqrt-x2-6x27-is-obtained-from-

Question

Use a shift to explain how the graph of h(x)=−x2−6x+27h(x)=\sqrt{$$-x^2-6x+27$$} is obtained from the graph of p(x)=36−x2p(x)=\sqrt{$$36-x^2$$}. Also, draw the graph of h(x)h\left(x\right).

Accepted Answer

Shift the graph of p(x)p(x) to the left by 33 units

Answer

Shift the graph of p(x)p(x) to the right by 33 units

Answer

Stretch the graph of p(x)p(x) vertically by a factor of 33

Use a shift to explain how the graph of h(x)=−x2−6x+27h(x)=\(\sqrt{-x^2-6x+27}\) is obtained from the graph of p(x)=36−x2p(x)=\(\sqrt{36-x^2}\). Also, draw the graph of h(x)h\(\left\)(x\(\right\)).

Use a shift to explain how the graph of $h (x) = \sqrt{- x^{2} - 6 x + 27}$ is obtained from the graph of $p (x) = \sqrt{36 - x^{2}}$ . Also, draw the graph of $h (x)$ .