Solve the following equations.cos⁡3x=sin⁡3x,0≤x\u003c2π\cos3x=\sin3x,0\leq{x}\lt2\picos3x=sin3x,0≤x\u003c2π

Ch. 1 - Functions

Briggs - Calculus: Early Transcendentals 3rd Edition

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Briggs 3rd Edition

Ch. 1 - Functions

문제 43

1장, 문제 43

Solve the following equations.
$\cos\)3x=$\sin$3x,0$\leq{x}\]\lt$2\(\pi$

검증된 단계별 안내

Start by recognizing that the equation $ \cos 3x = \sin 3x $ can be rewritten using the identity $ \tan \theta = \frac{\sin \theta}{\cos \theta} $. This gives us $ \tan 3x = 1 $.

Recall that $ \tan \theta = 1 $ at specific angles. The general solution for $ \tan \theta = 1 $ is $ \theta = \frac{\pi}{4} + n\pi $, where $ n $ is an integer.

Apply this general solution to $ 3x $, giving $ 3x = \frac{\pi}{4} + n\pi $.

Solve for $ x $ by dividing the entire equation by 3: $ x = \frac{\pi}{12} + \frac{n\pi}{3} $.

Determine the values of $ n $ such that $ 0 \leq x < 2\pi $. Substitute different integer values for $ n $ and solve for $ x $ to find all solutions within the given interval.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Trigonometric Identities

Trigonometric identities are equations that involve trigonometric functions and are true for all values of the variables involved. Key identities include the Pythagorean identity, angle sum and difference identities, and double angle formulas. In this problem, recognizing that \\cos(3x) = \\sin(3x) can be transformed using the identity \\tan(3x) = 1, which simplifies the process of finding solutions.

Solving Trigonometric Equations

Solving trigonometric equations involves finding the angles that satisfy the equation within a specified interval. This often requires manipulating the equation to isolate the trigonometric function and then using inverse trigonometric functions or known values. In this case, we need to find values of x such that \\tan(3x) = 1, which leads to specific angles that can be calculated within the given range of 0 to 2π.

Periodic Functions

Periodic functions are functions that repeat their values in regular intervals or periods. The sine and cosine functions are periodic with a period of 2π. When solving the equation \\cos(3x) = \\sin(3x), it is important to consider the periodic nature of these functions, as solutions may occur at multiple angles within the specified interval due to their periodicity, specifically every π/4 radians for this equation.

Solve the following equations.cos3x=sin3x,0≤x<2π\(\cos\)3x=\(\sin\)3x,0\(\leq{x}\]\lt\)2\(\pi\)cos3x=sin3x,0≤x<2π

비슷한 문제에 대한 검증된 영상 답변:

주요 개념

Trigonometric Identities

Solving Trigonometric Equations

Periodic Functions

Solve the following equations.
$\cos\)3x=\(\sin\)3x,0\(\leq{x}\]\lt\)2\(\pi$