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Ch. 10 - Sequences and Infinite Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
10장, 문제 10.1.23

"21–26. Recurrence relations Write the first four terms of the sequence {aₙ} defined by the following recurrence relations.
aₙ₊₁ = 3aₙ-12; a₁ = 10

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Identify the given recurrence relation: \(a_{n+1} = 3a_n - 12\) with the initial term \(a_1 = 10\).
Calculate the second term \(a_2\) by substituting \(n=1\) into the recurrence relation: \(a_2 = 3a_1 - 12\).
Calculate the third term \(a_3\) by substituting \(n=2\): \(a_3 = 3a_2 - 12\).
Calculate the fourth term \(a_4\) by substituting \(n=3\): \(a_4 = 3a_3 - 12\).
List the first four terms of the sequence as \(a_1\), \(a_2\), \(a_3\), and \(a_4\) after computing each step.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Recurrence Relations

A recurrence relation defines each term of a sequence using previous terms. It provides a formula to generate terms step-by-step, starting from initial values. Understanding how to apply the relation repeatedly is essential to find subsequent terms.
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04:16
Intro To Related Rates

Initial Conditions

Initial conditions specify the starting values of a sequence, such as a₁ = 10. These values are necessary to begin the process of generating terms using the recurrence relation, as they anchor the sequence and allow computation of all following terms.
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05:03
Initial Value Problems

Iterative Computation of Terms

To find terms of a sequence defined by a recurrence relation, you substitute known terms into the relation repeatedly. This iterative process involves calculating each term step-by-step, using the previous term(s) and the given formula.
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05:44
Divergence Test (nth Term Test)