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Ch. 10 - Sequences and Infinite Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
10장, 문제 10.R.55

42–76. Convergence or divergence Use a convergence test of your choice to determine whether the following series converge.
∑ (from k = 1 to ∞)k! / (eᵏ kᵏ)

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Identify the series given: \( \sum_{k=1}^{\infty} \frac{k!}{e^{k} k^{k}} \). We want to determine if this infinite series converges or diverges.
Consider using the Ratio Test, which is often effective for series involving factorials and exponential terms. The Ratio Test states that for \( a_k \), if \( L = \lim_{k \to \infty} \left| \frac{a_{k+1}}{a_k} \right| \), then the series converges if \( L < 1 \), diverges if \( L > 1 \), and is inconclusive if \( L = 1 \).
Write the ratio \( \frac{a_{k+1}}{a_k} \) explicitly: \[ \frac{a_{k+1}}{a_k} = \frac{\frac{(k+1)!}{e^{k+1} (k+1)^{k+1}}}{\frac{k!}{e^{k} k^{k}}} = \frac{(k+1)!}{e^{k+1} (k+1)^{k+1}} \times \frac{e^{k} k^{k}}{k!} \].
Simplify the expression by canceling factorial terms and exponential terms: \( (k+1)! = (k+1) \times k! \) and \( e^{k+1} = e^{k} \times e \). Substitute these to get a simpler form for the ratio.
After simplification, take the limit as \( k \to \infty \) of the ratio. Use properties of limits and approximations such as \( \left(1 + \frac{1}{k}\right)^k \approx e \) to evaluate the limit and determine whether it is less than, greater than, or equal to 1, which will tell you about the convergence or divergence of the series.

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주요 개념

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Infinite Series and Convergence

An infinite series is the sum of infinitely many terms. Determining whether such a series converges means checking if the sum approaches a finite limit as the number of terms grows indefinitely. Understanding convergence is essential to analyze the behavior of series like ∑ k! / (e^k k^k).
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가이드 코스
06:52
Convergence of an Infinite Series

Ratio Test

The Ratio Test is a common method to determine the convergence of a series by examining the limit of the absolute value of the ratio of consecutive terms. If this limit is less than 1, the series converges absolutely; if greater than 1, it diverges. This test is particularly useful for series involving factorials and exponentials.
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Factorials and Exponential Growth

Factorials (k!) grow very rapidly, but so do exponential functions like e^k and powers like k^k. Comparing the growth rates of these terms helps in applying convergence tests effectively. Recognizing how factorials and exponentials behave is crucial for simplifying terms and evaluating limits in series.
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5:22
Factorials