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Ch. 11 - Power Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
11장, 문제 11.4.65c

Explain why or why not Determine whether the following statements are true and give an explanation or counterexample.


c. ∑ₖ₌₀∞ (ln 2)ᵏ/k! = 2

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1
Recognize that the series given is an infinite sum of the form \(\sum_{k=0}^\infty \frac{(\ln 2)^k}{k!}\), which resembles the Taylor series expansion of the exponential function \(e^x = \sum_{k=0}^\infty \frac{x^k}{k!}\).
Identify that in this series, \(x = \ln 2\), so the sum can be rewritten as \(\sum_{k=0}^\infty \frac{(\ln 2)^k}{k!} = e^{\ln 2}\).
Recall the property of exponentials and logarithms that \(e^{\ln a} = a\) for any positive \(a\), so \(e^{\ln 2} = 2\).
Conclude that the series converges to 2, which means the statement \(\sum_{k=0}^\infty \frac{(\ln 2)^k}{k!} = 2\) is true.
Therefore, the explanation is that the series is the exponential series evaluated at \(\ln 2\), and by the fundamental properties of logarithms and exponentials, the sum equals 2.

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주요 개념

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An infinite series is the sum of infinitely many terms. Understanding whether such a series converges (approaches a finite limit) or diverges is crucial. Convergence tests and recognizing known series forms help determine the sum or behavior of the series.
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The exponential function e^x can be expressed as the infinite series ∑ₖ₌₀∞ xᵏ/k!. This power series converges for all real x and provides a way to evaluate sums involving factorial denominators and powers, linking series to exponential functions.
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The natural logarithm ln(x) is the inverse of the exponential function e^x. Knowing that e^(ln a) = a allows substitution in series expressions, which helps simplify and evaluate series involving powers of ln(2) by relating them to powers of e.
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