Evaluate d/dx(x sec^−1 x) |x = 2 /√3.

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First, recognize that you need to differentiate the function f(x) = x sec^(-1)(x) with respect to x. This requires the use of the product rule for differentiation.

Recall the product rule: if you have a function h(x) = u(x) * v(x), then the derivative h'(x) = u'(x) * v(x) + u(x) * v'(x). Here, let u(x) = x and v(x) = sec^(-1)(x).

Differentiate u(x) = x to get u'(x) = 1.

Differentiate v(x) = sec^(-1)(x). The derivative of sec^(-1)(x) with respect to x is 1 / (|x| * sqrt(x^2 - 1)).

Apply the product rule: f'(x) = 1 * sec^(-1)(x) + x * (1 / (|x| * sqrt(x^2 - 1))). Finally, substitute x = 2/√3 into this expression to evaluate the derivative at that point.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Derivative

The derivative of a function measures how the function's output value changes as its input value changes. It is a fundamental concept in calculus, representing the slope of the tangent line to the curve at a given point. The notation d/dx indicates differentiation with respect to x, and finding the derivative is essential for understanding rates of change and optimizing functions.

Secant and Inverse Secant Functions

The secant function, denoted as sec(x), is the reciprocal of the cosine function, defined as sec(x) = 1/cos(x). The inverse secant function, sec^−1(x), returns the angle whose secant is x. Understanding these functions is crucial for evaluating expressions involving them, especially when differentiating products that include inverse trigonometric functions.

Product Rule

The product rule is a formula used to find the derivative of the product of two functions. It states that if u(x) and v(x) are two differentiable functions, then the derivative of their product is given by d/dx[u(x)v(x)] = u'(x)v(x) + u(x)v'(x). This rule is essential for solving the given problem, as it allows for the differentiation of the product x and sec^−1(x).