Skip to main content
Ch. 3 - Derivatives
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
3장, 문제 3.5.29

Find the derivative of the following functions.
y = cos x/sin x + 1

검증된 단계별 안내
1
Step 1: Recognize that the function y = \(\frac{\cos x}{\sin x}\) + 1 can be rewritten as y = \(\cot\) x + 1, where \(\cot\) x is the cotangent function.
Step 2: Recall the derivative of the cotangent function: \(\frac{d}{dx}\)(\(\cot\) x) = -\(\csc\)^2 x.
Step 3: Differentiate the function y = \(\cot\) x + 1 with respect to x. The derivative of a constant (1 in this case) is 0.
Step 4: Apply the derivative rule from Step 2 to find the derivative of \(\cot\) x, which is -\(\csc\)^2 x.
Step 5: Combine the results from Steps 3 and 4 to express the derivative of the entire function: \(\frac{dy}{dx}\) = -\(\csc\)^2 x.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
3m
도움이 되었나요?

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Derivative

The derivative of a function measures how the function's output value changes as its input value changes. It is defined as the limit of the average rate of change of the function over an interval as the interval approaches zero. In calculus, the derivative is often denoted as f'(x) or dy/dx, and it provides critical information about the function's behavior, such as its slope and points of tangency.
추천 영상:

Trigonometric Functions

Trigonometric functions, such as sine (sin) and cosine (cos), are fundamental in calculus, especially when dealing with periodic phenomena. These functions relate angles to ratios of sides in right triangles and are essential for modeling oscillatory behavior. Understanding their derivatives, such as the fact that the derivative of cos(x) is -sin(x) and the derivative of sin(x) is cos(x), is crucial for solving problems involving these functions.
추천 영상:
가이드 코스
6:04
Introduction to Trigonometric Functions

Quotient Rule

The quotient rule is a method for finding the derivative of a function that is the ratio of two other functions. If y = u/v, where u and v are both differentiable functions, the derivative is given by y' = (v * u' - u * v') / v^2. This rule is particularly useful when differentiating functions like y = cos(x)/sin(x) + 1, as it allows for the systematic calculation of the derivative of the quotient of trigonometric functions.
추천 영상:
06:43
The Quotient Rule