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Ch. 3 - Derivatives
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
3장, 문제 3.6.9

The speed of sound (in m/s) in dry air is approximated the function v(T) = 331 + 0.6T, where T is the air temperature (in degrees Celsius). Evaluate v' (T) and interpret its meaning.

검증된 단계별 안내
1
Step 1: Identify the given function v(T) = 331 + 0.6T, which represents the speed of sound in dry air as a function of temperature T.
Step 2: Recognize that v'(T) represents the derivative of the function v(T) with respect to T, which gives the rate of change of the speed of sound with respect to temperature.
Step 3: Differentiate the function v(T) = 331 + 0.6T with respect to T. Since 331 is a constant, its derivative is 0. The derivative of 0.6T with respect to T is 0.6.
Step 4: Conclude that v'(T) = 0.6. This means that for each degree Celsius increase in temperature, the speed of sound increases by 0.6 meters per second.
Step 5: Interpret the result: The derivative v'(T) = 0.6 indicates that the speed of sound in dry air increases linearly with temperature at a constant rate of 0.6 m/s per degree Celsius.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
2m

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Derivative

The derivative of a function measures the rate at which the function's value changes as its input changes. In this context, v'(T) represents the rate of change of the speed of sound with respect to temperature. It provides insight into how sensitive the speed of sound is to variations in temperature.
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Function Interpretation

Understanding the function v(T) = 331 + 0.6T involves recognizing that it is a linear function where the speed of sound increases with temperature. The constant 331 m/s represents the speed of sound at 0 degrees Celsius, while the coefficient 0.6 indicates the increase in speed for each degree rise in temperature.
추천 영상:
04:39
Derivative of the Natural Logarithmic Function Example 7

Physical Context of Derivatives

In physics, derivatives often have practical interpretations. For this problem, v'(T) not only quantifies how the speed of sound changes with temperature but also reflects the physical phenomenon that sound travels faster in warmer air. This relationship is crucial for applications in meteorology and acoustics.
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