Area functions and the Fundamental Theorem Consider the functionƒ(t) = { t if ―2 ≤ t \u003c 0t²/2 if 0 ≤ t ≤ 2and its graph shown below. Let F(𝓍) = ∫₋₁ˣ ƒ(t) dt and G(𝓍) = ∫₋₂ˣ ƒ(t) dt.(d) Evaluate F ' (―1) and F ' (1). Interpret these values.

Ch. 5 - Integration

Briggs - Calculus: Early Transcendentals 3rd Edition

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Briggs 3rd Edition

Ch. 5 - Integration

문제 5.R.105d

5장, 문제 5.R.105d

Area functions and the Fundamental Theorem Consider the function
ƒ(t) = { t if ―2 ≤ t < 0
t²/2 if 0 ≤ t ≤ 2
and its graph shown below. Let F(𝓍) = ∫₋₁ˣ ƒ(t) dt and G(𝓍) = ∫₋₂ˣ ƒ(t) dt.

(d) Evaluate F ' (―1) and F ' (1). Interpret these values.

검증된 단계별 안내

Step 1: Recall the Fundamental Theorem of Calculus, which states that if F(x) = ∫ₐˣ ƒ(t) dt, then F'(x) = ƒ(x). This means the derivative of the area function F(x) is equal to the value of the function ƒ(x) at x.

Step 2: To evaluate F'(−1), observe that F'(x) = ƒ(x). From the graph and the piecewise definition of ƒ(t), for −2 ≤ t < 0, ƒ(t) = t. Therefore, ƒ(−1) = −1.

Step 3: To evaluate F'(1), observe again that F'(x) = ƒ(x). From the graph and the piecewise definition of ƒ(t), for 0 ≤ t ≤ 2, ƒ(t) = t²/2. Therefore, ƒ(1) = (1²)/2 = 1/2.

Step 4: Interpret the values: F'(−1) = −1 indicates that at x = −1, the rate of change of the area function F(x) is equal to the value of ƒ(t) at t = −1, which is −1. Similarly, F'(1) = 1/2 indicates that at x = 1, the rate of change of the area function F(x) is equal to the value of ƒ(t) at t = 1, which is 1/2.

Step 5: The values of F'(−1) and F'(1) provide insight into how the function ƒ(t) contributes to the accumulation of area in F(x) at specific points. Negative values of ƒ(t) (e.g., at t = −1) reduce the accumulated area, while positive values (e.g., at t = 1) increase it.

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주요 개념

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Fundamental Theorem of Calculus

The Fundamental Theorem of Calculus links the concept of differentiation and integration, stating that if F is an antiderivative of f on an interval [a, b], then the integral of f from a to b is equal to F(b) - F(a). This theorem allows us to evaluate definite integrals and understand the relationship between a function and its area under the curve.

Derivative of an Integral Function

When evaluating the derivative of an integral function, such as F(x) = ∫₋₁ˣ f(t) dt, we apply the Fundamental Theorem of Calculus. The derivative F'(x) gives us the value of the integrand f evaluated at the upper limit of integration, which provides insight into the rate of change of the area under the curve as x varies.

Piecewise Functions

A piecewise function is defined by different expressions based on the input value. In this case, the function f(t) has two distinct expressions depending on whether t is less than 0 or between 0 and 2. Understanding how to evaluate and differentiate piecewise functions is crucial for correctly applying calculus concepts to such functions.

Area functions and the Fundamental Theorem Consider the functionƒ(t) = { t if ―2 ≤ t < 0t²/2 if 0 ≤ t ≤ 2and its graph shown below. Let F(𝓍) = ∫₋₁ˣ ƒ(t) dt and G(𝓍) = ∫₋₂ˣ ƒ(t) dt.(d) Evaluate F ' (―1) and F ' (1). Interpret these values.