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Ch. 5 - Integration
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
5장, 문제 5.4.38

Average height of a wave The surface of a water wave is described by y = 5 (1 + cos 𝓍) , for ― π ≤ 𝓍 ≤ π, where y = 0 corresponds to a trough of the wave (see figure). Find the average height of the wave above the trough on [ ―π , π] .
Graph of the wave function y = 5(1 + cos x) showing its height from trough to peak over the interval from -π to π.

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Step 1: Understand the problem. The goal is to find the average height of the wave above the trough over the interval [−π, π]. The wave is described by the function y = 5(1 + cos(x)), where y = 0 corresponds to the trough.
Step 2: Recall the formula for the average value of a function f(x) over an interval [a, b]: Average value = (1 / (b - a)) * ∫[a to b] f(x) dx. Here, f(x) = 5(1 + cos(x)), a = −π, and b = π.
Step 3: Set up the integral for the average value. Substitute the given function and interval into the formula: Average value = (1 / (π - (−π))) * ∫[−π to π] 5(1 + cos(x)) dx.
Step 4: Simplify the expression. The denominator becomes 2π, so Average value = (1 / 2π) * ∫[−π to π] 5(1 + cos(x)) dx. Factor out the constant 5 from the integral: Average value = (5 / 2π) * ∫[−π to π] (1 + cos(x)) dx.
Step 5: Break the integral into two parts: ∫[−π to π] (1 + cos(x)) dx = ∫[−π to π] 1 dx + ∫[−π to π] cos(x) dx. Evaluate each integral separately. The integral of 1 over [−π, π] is straightforward, and the integral of cos(x) over [−π, π] can be solved using trigonometric properties.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Average Value of a Function

The average value of a continuous function over an interval is calculated using the formula: (1/(b-a)) * ∫[a to b] f(x) dx. This concept is essential for determining the average height of the wave, as it allows us to find the mean value of the function y = 5(1 + cos x) over the specified interval from -π to π.
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06:37
Average Value of a Function

Integration

Integration is a fundamental concept in calculus that involves finding the area under a curve represented by a function. In this context, we will use definite integration to calculate the total area under the wave function y = 5(1 + cos x) over the interval [-π, π], which is necessary for computing the average height of the wave.
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가이드 코스
06:18
Integration by Parts for Definite Integrals

Cosine Function Properties

The cosine function is periodic and oscillates between -1 and 1. In the given wave function y = 5(1 + cos x), the term (1 + cos x) shifts the graph vertically, ensuring that the wave's height is always non-negative. Understanding the behavior of the cosine function is crucial for analyzing the wave's shape and determining its average height above the trough.
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가이드 코스
06:21
Properties of Functions
관련 실천
교과서 질문

Indefinite integrals Use a change of variables or Table 5.6 to evaluate the following indefinite integrals. Check your work by differentiating.                                                                                  

                                                                                                                                                                    

 ∫ 𝓍eˣ² d𝓍

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교과서 질문

A midpoint Riemann sum Approximate the area of the region bounded by the graph of ƒ(𝓍) = 100 ― x² and the x-axis on [0, 10] with n = 5 subintervals. Use the midpoint of each subinterval to determine the height of each rectangle (see figure).

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교과서 질문

Indefinite integrals Use a change of variables or Table 5.6 to evaluate the following indefinite integrals. Check your work by differentiating.                                                                                  

                                                                                                                                                                    

 ∫ 𝓍³ (𝓍⁴ + 16)⁶ d𝓍

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교과서 질문

Areas of regions Find the area of the region bounded by the graph of ƒ and the 𝓍-axis on the given interval.


ƒ(𝓍) = 𝓍³ ― 1 on [―1, 2]

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교과서 질문

Approximating displacement The velocity of an object is given by the following functions on a specified interval. Approximate the displacement of the object on this interval by subdividing the interval into n subintervals. Use the left endpoint of each subinterval to compute the height of the rectangles.

{Use of Tech} v = 4 √(t +1) (mi/hr) . for 0 ≤ t ≤ 15 ; n = 5     

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교과서 질문

Derivatives of integrals Simplify the following expressions.


d/dz ∫¹⁰ₛᵢₙ ₂ dt /(t⁴ + 1)

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