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Ch. 5 - Integration
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
5장, 문제 5.3.81

Derivatives of integrals Simplify the following expressions.


d/dz ∫¹⁰ₛᵢₙ ₂ dt /(t⁴ + 1)

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Step 1: Recognize that the problem involves the derivative of an integral. This is a classic application of the Fundamental Theorem of Calculus, which states that if F(x) = ∫[a(x), b(x)] f(t) dt, then dF/dx = f(b(x)) * b'(x) - f(a(x)) * a'(x).
Step 2: Identify the bounds of the integral. The upper bound is 10, which is constant, and the lower bound is sin(z), which is a function of z. This means the derivative will involve the lower bound's derivative.
Step 3: Apply the Fundamental Theorem of Calculus. Since the upper bound is constant, its derivative contributes nothing. For the lower bound, substitute t = sin(z) into the integrand f(t) = 1/(t⁴ + 1), and multiply by the derivative of sin(z), which is cos(z).
Step 4: Write the expression for the derivative. The result is -[1/(sin(z)⁴ + 1)] * cos(z). The negative sign comes from the fact that the lower bound contributes negatively in the Fundamental Theorem of Calculus.
Step 5: Simplify the expression if needed. The derivative is now expressed in terms of z, and no further simplification is required unless specified.

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주요 개념

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Fundamental Theorem of Calculus

The Fundamental Theorem of Calculus links differentiation and integration, stating that if F is an antiderivative of f on an interval [a, b], then the integral of f from a to b can be computed as F(b) - F(a). This theorem also implies that the derivative of an integral function is the integrand evaluated at the upper limit of integration, which is crucial for simplifying expressions involving derivatives of integrals.
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가이드 코스
06:11
Fundamental Theorem of Calculus Part 1

Definite Integral

A definite integral represents the signed area under a curve defined by a function over a specific interval [a, b]. It is denoted as ∫_a^b f(x) dx and provides a numerical value that reflects the accumulation of quantities, such as area or total change, over that interval. Understanding how to evaluate definite integrals is essential for applying the Fundamental Theorem of Calculus.
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가이드 코스
05:43
Definition of the Definite Integral

Chain Rule

The Chain Rule is a fundamental principle in calculus used to differentiate composite functions. It states that if a function y = f(g(x)) is composed of two functions, the derivative dy/dx can be found by multiplying the derivative of the outer function f with respect to g by the derivative of the inner function g with respect to x. This rule is particularly useful when dealing with integrals that have variable limits, as seen in the given expression.
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Intro to the Chain Rule
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Average height of a wave The surface of a water wave is described by y = 5 (1 + cos 𝓍) , for ― π ≤ 𝓍 ≤ π, where y = 0 corresponds to a trough of the wave (see figure). Find the average height of the wave above the trough on [ ―π , π] .

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Areas of regions Find the area of the region bounded by the graph of ƒ and the 𝓍-axis on the given interval.


ƒ(𝓍) = 𝓍³ ― 1 on [―1, 2]

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{Use of Tech} v = 4 √(t +1) (mi/hr) . for 0 ≤ t ≤ 15 ; n = 5     

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Mean Value Theorem for Integrals Find or approximate all points at which the given function equals its average value on the given interval.


ƒ(𝓍) = 8 ― 2𝓍 on [0, 4]

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Variations on the substitution method Evaluate the following integrals.                                                                                                        

                                                                                                                                                                    

 ∫ 𝓍/(∛𝓍 + 4) d𝓍

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