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Ch. 5 - Integration
5์žฅ, ๋ฌธ์ œ 5.RE.15c

Symmetry properties Suppose โˆซโ‚€โด ฦ’(๐“) d๐“ = 10 and โˆซโ‚€โด g(๐“) d๐“ = 20. Furthermore, suppose ฦ’ is an even function and g is an odd function. Evaluate the following integrals.


(c) โˆซโ‚‹โ‚„โด (4ฦ’(๐“) โ€• 3g(๐“))d๐“

๊ฒ€์ฆ๋œ ๋‹จ๊ณ„๋ณ„ ์•ˆ๋‚ด
1
Step 1: Recall the symmetry properties of even and odd functions. An even function satisfies ฦ’(๐“) = ฦ’(โˆ’๐“), and its integral over a symmetric interval [โˆ’a, a] is twice the integral over [0, a]. An odd function satisfies g(๐“) = โˆ’g(โˆ’๐“), and its integral over a symmetric interval [โˆ’a, a] is 0.
Step 2: Break the given integral โˆซโ‚‹โ‚„โด (4ฦ’(๐“) โ€• 3g(๐“)) d๐“ into two separate integrals: โˆซโ‚‹โ‚„โด 4ฦ’(๐“) d๐“ and โˆซโ‚‹โ‚„โด โˆ’3g(๐“) d๐“. This uses the linearity property of integrals.
Step 3: For the first term, โˆซโ‚‹โ‚„โด 4ฦ’(๐“) d๐“, note that ฦ’(๐“) is an even function. Therefore, โˆซโ‚‹โ‚„โด ฦ’(๐“) d๐“ = 2โˆซโ‚€โด ฦ’(๐“) d๐“. Multiply this result by 4 to account for the coefficient.
Step 4: For the second term, โˆซโ‚‹โ‚„โด โˆ’3g(๐“) d๐“, note that g(๐“) is an odd function. The integral of an odd function over a symmetric interval [โˆ’a, a] is 0. Therefore, this term evaluates to 0.
Step 5: Combine the results from Step 3 and Step 4. The final integral โˆซโ‚‹โ‚„โด (4ฦ’(๐“) โ€• 3g(๐“)) d๐“ simplifies to the result obtained from the first term, as the second term is 0.

๋น„์Šทํ•œ ๋ฌธ์ œ์— ๋Œ€ํ•œ ๊ฒ€์ฆ๋œ ์˜์ƒ ๋‹ต๋ณ€:

์ด ์˜์ƒ ํ•ด๋ฒ•์€ ์œ„ ๋ฌธ์ œ์— ๋„์›€์ด ๋œ๋‹ค๊ณ  ํŠœํ„ฐ๋“ค์ด ์ถ”์ฒœํ•œ ๊ฒƒ์ž…๋‹ˆ๋‹ค.
์˜์ƒ ๊ธธ์ด:
3m

์ฃผ์š” ๊ฐœ๋…

์งˆ๋ฌธ์— ์˜ฌ๋ฐ”๋ฅด๊ฒŒ ๋‹ตํ•˜๊ธฐ ์œ„ํ•ด ๋ฐ˜๋“œ์‹œ ์ดํ•ดํ•ด์•ผ ํ•˜๋Š” ํ•ต์‹ฌ ๊ฐœ๋…๋“ค์€ ๋‹ค์Œ๊ณผ ๊ฐ™์Šต๋‹ˆ๋‹ค.

Even and Odd Functions

An even function satisfies the property f(-x) = f(x) for all x in its domain, meaning its graph is symmetric about the y-axis. Conversely, an odd function satisfies g(-x) = -g(x), indicating symmetry about the origin. These properties are crucial for evaluating integrals over symmetric intervals, as they allow simplifications based on the behavior of the functions.
์ถ”์ฒœ ์˜์ƒ:

Properties of Definite Integrals

Definite integrals have specific properties that can simplify calculations. For instance, the integral of an even function over a symmetric interval [-a, a] is twice the integral from 0 to a, while the integral of an odd function over the same interval is zero. These properties help in evaluating integrals without direct computation.
์ถ”์ฒœ ์˜์ƒ:
๊ฐ€์ด๋“œ ์ฝ”์Šค
05:43
Definition of the Definite Integral

Linear Combination of Integrals

The linearity of integrals allows us to combine integrals of functions through addition and scalar multiplication. Specifically, โˆซ(af(x) + bg(x))dx = aโˆซf(x)dx + bโˆซg(x)dx, where a and b are constants. This property is essential for evaluating integrals involving multiple functions, as it enables the separation of terms for easier computation.
์ถ”์ฒœ ์˜์ƒ:
๊ด€๋ จ ์‹ค์ฒœ
๊ต๊ณผ์„œ ์งˆ๋ฌธ

Zero net area Consider the function ฦ’(๐“) = ๐“ยฒ โ€• 4๐“ .

(a) Graph ฦ’ on the interval ๐“ โ‰ฅ 0.

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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Evaluating integrals Evaluate the following integrals.


โˆซโ‚€ยน ๐“ โ€ข 2หฃยฒโบยน d๐“

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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Symmetry properties Suppose โˆซโ‚€โด ฦ’(๐“) d๐“ = 10 and โˆซโ‚€โด g(๐“) d๐“ = 20. Furthermore, suppose ฦ’ is an even function and g is an odd function. Evaluate the following integrals.


(e) โˆซโ‚‹โ‚‚ยฒ 3๐“ฦ’(๐“)d๐“

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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Explain why or why not Determine whether the following statements are true and give an explanation or counterexample.

(a) Consider the linear function ฦ’(๐“) = 2x + 5 and the region bounded by its graph and the x-axis on the interval [3,6]. Suppose the area of this region is approximated using midpoint Riemann sums. Then the approximations give the exact area of the region for any number of subintervals.

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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Symmetry properties Suppose โˆซโ‚€โด ฦ’(๐“) d๐“ = 10 and โˆซโ‚€โด g(๐“) d๐“ = 20. Furthermore, suppose ฦ’ is an even function and g is an odd function. Evaluate the following integrals.


(a) โˆซโ‚‹โ‚„โด ฦ’(๐“) d๐“

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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Working with area functions Consider the function ฦ’ and the points a, b, and c.

(a) Find the area function A (๐“) = โˆซโ‚หฃ ฦ’(t) dt using the Fundamental Theorem.

ฦ’(๐“) = sin ๐“ ; a = 0 , b = ฯ€/2 , c = ฯ€

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