Skip to main content
Ch. 5 - Integration
5์žฅ, ๋ฌธ์ œ 5.3.111a

Zero net area Consider the function ฦ’(๐“) = ๐“ยฒ โ€• 4๐“ .
(a) Graph ฦ’ on the interval ๐“ โ‰ฅ 0.

๊ฒ€์ฆ๋œ ๋‹จ๊ณ„๋ณ„ ์•ˆ๋‚ด
1
Step 1: Start by analyzing the given function ฦ’(๐“) = ๐“ยฒ - 4๐“. Identify its key features, such as the degree of the polynomial (quadratic) and the leading coefficient (positive, indicating the parabola opens upwards).
Step 2: Find the critical points of the function by taking its derivative. Compute ฦ’'(๐“) = d/d๐“ [๐“ยฒ - 4๐“] = 2๐“ - 4. Set ฦ’'(๐“) = 0 to solve for ๐“, which gives the critical points.
Step 3: Determine the vertex of the parabola. The vertex occurs at ๐“ = -b/(2a) for a quadratic function in the form axยฒ + bx + c. Here, a = 1 and b = -4, so the vertex is at ๐“ = 2. Evaluate ฦ’(2) to find the corresponding y-coordinate of the vertex.
Step 4: Identify the x-intercepts by solving ฦ’(๐“) = 0. Factorize the quadratic equation ๐“ยฒ - 4๐“ = 0 as ๐“(๐“ - 4) = 0, which gives the solutions ๐“ = 0 and ๐“ = 4. These are the points where the graph crosses the x-axis.
Step 5: Plot the graph of ฦ’(๐“) on the interval ๐“ โ‰ฅ 0. Mark the vertex, x-intercepts, and other key points. Sketch the parabola, ensuring it opens upwards and passes through the identified points.

๋น„์Šทํ•œ ๋ฌธ์ œ์— ๋Œ€ํ•œ ๊ฒ€์ฆ๋œ ์˜์ƒ ๋‹ต๋ณ€:

์ด ์˜์ƒ ํ•ด๋ฒ•์€ ์œ„ ๋ฌธ์ œ์— ๋„์›€์ด ๋œ๋‹ค๊ณ  ํŠœํ„ฐ๋“ค์ด ์ถ”์ฒœํ•œ ๊ฒƒ์ž…๋‹ˆ๋‹ค.
์˜์ƒ ๊ธธ์ด:
2m
๋„์›€์ด ๋˜์—ˆ๋‚˜์š”?

์ฃผ์š” ๊ฐœ๋…

์งˆ๋ฌธ์— ์˜ฌ๋ฐ”๋ฅด๊ฒŒ ๋‹ตํ•˜๊ธฐ ์œ„ํ•ด ๋ฐ˜๋“œ์‹œ ์ดํ•ดํ•ด์•ผ ํ•˜๋Š” ํ•ต์‹ฌ ๊ฐœ๋…๋“ค์€ ๋‹ค์Œ๊ณผ ๊ฐ™์Šต๋‹ˆ๋‹ค.

Graphing Functions

Graphing functions involves plotting points on a coordinate plane to visualize the relationship between the input (x-values) and output (y-values) of a function. For the function ฦ’(๐“) = ๐“ยฒ - 4๐“, this means calculating y-values for various x-values, particularly within the specified interval x โ‰ฅ 0, and connecting these points to form a continuous curve.
์ถ”์ฒœ ์˜์ƒ:
๊ฐ€์ด๋“œ ์ฝ”์Šค
5:53
Graph of Sine and Cosine Function

Finding Roots

Finding the roots of a function refers to determining the values of x for which the function equals zero. For ฦ’(๐“) = ๐“ยฒ - 4๐“, this involves solving the equation ๐“ยฒ - 4๐“ = 0, which can be factored to find the x-intercepts. These roots are critical for understanding where the graph intersects the x-axis and can indicate changes in the function's behavior.
์ถ”์ฒœ ์˜์ƒ:

Understanding Area Under the Curve

The area under the curve of a function on a given interval can provide insights into the function's behavior, such as net area, which accounts for regions above and below the x-axis. In this case, analyzing the graph of ฦ’(๐“) = ๐“ยฒ - 4๐“ will help determine if the net area is zero, which occurs when the positive and negative areas cancel each other out within the specified interval.
์ถ”์ฒœ ์˜์ƒ:
๊ฐ€์ด๋“œ ์ฝ”์Šค
05:59
Estimating the Area Under a Curve with Right Endpoints & Midpoint
๊ด€๋ จ ์‹ค์ฒœ
๊ต๊ณผ์„œ ์งˆ๋ฌธ

Displacement from a velocity graph Consider the velocity function for an object moving along a line (see figure).

(a) Describe the motion of the object over the interval [0,6].

76
views
๊ต๊ณผ์„œ ์งˆ๋ฌธ

Suppose ฦ’ is an odd function, โˆซโ‚€โด ฦ’(๐“) d๐“ = 3 , and โˆซโ‚€โธ ฦ’(๐“) d๐“ = 9 .


(a) Evaluate โˆซโ‚‹โ‚ˆโด ฦ’(๐“) d๐“ .

73
views
๊ต๊ณผ์„œ ์งˆ๋ฌธ

Free fall On October 14, 2012, Felix Baumgartner stepped off a balloon capsule at an altitude of almost 39 km above Earthโ€™s surface and began his free fall. His velocity in m/s during the fall is given in the figure. It is claimed that Felix reached the speed of sound 34 seconds into his fall and that he continued to fall at supersonic speed for 30 seconds. (Source: http://www.redbullstratos.com)

(a) Divide the interval [34, 64] into n = 5 subintervals with the gridpoints xโ‚€ = 34 , xโ‚ = 40 , xโ‚‚ = 46 , xโ‚ƒ = 52 , xโ‚„ = 58 , and xโ‚… = 64. Use left and right Riemann sums to estimate how far Felix fell while traveling at supersonic speed.

64
views
๊ต๊ณผ์„œ ์งˆ๋ฌธ

The velocity in ft/s of an object moving along a line is given by v = ฦ’(t) on the interval 0 โ‰ค t โ‰ค 6 (see figure), where t is measured in seconds.


(a) Divide the interval [0,6] into n = 3 subintervals, [0,2] , [2,4] and [4,6]. On each subinterval, assume the object moves at a constant velocity equal to the value of v evaluated at the right endpoint of the subinterval, and use these approximations to estimate the displacement of the object on [0,6] (see part (a) of the figure)                                                                                                             

                                                                                                                                                                                                

67
views
๊ต๊ณผ์„œ ์งˆ๋ฌธ

Sigma notation Evaluate the following expressions.

(a)    10                                                                                                                                                                               

       โˆ‘ ฮบ                                                                                                                                                                          

       ฮบ=1                         

64
views
๊ต๊ณผ์„œ ์งˆ๋ฌธ

Explain why or why not Determine whether the following statements are true and give an explanation or counterexample.

(a) If ฦ’ is a constant function on the interval [a,b], then the right and left Riemann sums give the exact value of โˆซโ‚แต‡ ฦ’(๐“) d๐“, for any positive integer n.

66
views