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Ch. 5 - Integration
5์žฅ, ๋ฌธ์ œ 5.5.3

The composite function ฦ’(g(๐“)) consists of an inner function g and an outer function ฦ’. If an integrand includes ฦ’(g(๐“)), which function is often a likely choice for a new variable u?

๊ฒ€์ฆ๋œ ๋‹จ๊ณ„๋ณ„ ์•ˆ๋‚ด
1
Identify the composite function given as ฦ’(g(๐“)), where g(๐“) is the inner function and ฦ’ is the outer function.
Recall that when performing integration involving composite functions, substitution is a common technique to simplify the integral.
In substitution, we typically choose the inner function g(๐“) as the new variable u because it simplifies the integrand and its differential du relates directly to dx.
Express the substitution as u = g(๐“), then compute the differential du = g\' (๐“) d๐“ to replace parts of the integral accordingly.
Rewrite the integral entirely in terms of u and du, which often makes the integral easier to evaluate.

๋น„์Šทํ•œ ๋ฌธ์ œ์— ๋Œ€ํ•œ ๊ฒ€์ฆ๋œ ์˜์ƒ ๋‹ต๋ณ€:

์ด ์˜์ƒ ํ•ด๋ฒ•์€ ์œ„ ๋ฌธ์ œ์— ๋„์›€์ด ๋œ๋‹ค๊ณ  ํŠœํ„ฐ๋“ค์ด ์ถ”์ฒœํ•œ ๊ฒƒ์ž…๋‹ˆ๋‹ค.
์˜์ƒ ๊ธธ์ด:
1m
๋„์›€์ด ๋˜์—ˆ๋‚˜์š”?

์ฃผ์š” ๊ฐœ๋…

์งˆ๋ฌธ์— ์˜ฌ๋ฐ”๋ฅด๊ฒŒ ๋‹ตํ•˜๊ธฐ ์œ„ํ•ด ๋ฐ˜๋“œ์‹œ ์ดํ•ดํ•ด์•ผ ํ•˜๋Š” ํ•ต์‹ฌ ๊ฐœ๋…๋“ค์€ ๋‹ค์Œ๊ณผ ๊ฐ™์Šต๋‹ˆ๋‹ค.

Composite Functions

A composite function is formed when one function is applied to the result of another, written as ฦ’(g(x)). Understanding how the inner function g(x) and outer function ฦ’ relate is essential for manipulating and simplifying expressions involving compositions.
์ถ”์ฒœ ์˜์ƒ:
3:48
Evaluate Composite Functions - Special Cases

U-Substitution Method

U-substitution is a technique used in integration where a new variable u is chosen to simplify the integral. Typically, u is set equal to the inner function g(x) in a composite function to make the integral easier to evaluate.
์ถ”์ฒœ ์˜์ƒ:
04:27
Substitution With an Extra Variable

Chain Rule in Integration

The chain rule relates the derivative of a composite function to the derivatives of its inner and outer functions. In integration, recognizing this structure helps identify the inner function as a candidate for substitution, reversing the chain rule process.
์ถ”์ฒœ ์˜์ƒ:
05:02
Intro to the Chain Rule
๊ด€๋ จ ์‹ค์ฒœ
๊ต๊ณผ์„œ ์งˆ๋ฌธ

Areas of regions Find the area of the region bounded by the graph of ฦ’ and the ๐“-axis on the given interval.


ฦ’(๐“) = ๐“ยณ โ€• 1 on [โ€•1, 2]

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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Approximating displacement The velocity of an object is given by the following functions on a specified interval. Approximate the displacement of the object on this interval by subdividing the interval into n subintervals. Use the left endpoint of each subinterval to compute the height of the rectangles.

{Use of Tech} v = 4 โˆš(t +1) (mi/hr) . for 0 โ‰ค t โ‰ค 15 ; n = 5     

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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Derivatives of integrals Simplify the following expressions.


d/dz โˆซยนโฐโ‚›แตขโ‚™ โ‚‚ dt /(tโด + 1)

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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Mean Value Theorem for Integrals Find or approximate all points at which the given function equals its average value on the given interval.


ฦ’(๐“) = 8 โ€• 2๐“ on [0, 4]

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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Variations on the substitution method Evaluate the following integrals.                                                                                                        

                                                                                                                                                                    

 โˆซ ๐“/(โˆ›๐“ + 4) d๐“

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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Evaluate โˆซโ‚ƒโธ ฦ’ โ€ฒ(t) dt , where ฦ’ โ€ฒ is continuous on [3, 8], ฦ’(3) = 4, and ฦ’(8) = 20 .

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