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Ch. 5 - Integration
5์žฅ, ๋ฌธ์ œ 5.3.5

The linear function ฦ’(๐“) = 3 โ€• ๐“ is decreasing on the interval [0, 3]. Is its area function for ฦ’ (with left endpoint 0) increasing or decreasing on the interval [0, 3]? Draw a picture and explain. 

๊ฒ€์ฆ๋œ ๋‹จ๊ณ„๋ณ„ ์•ˆ๋‚ด
1
Step 1: Understand the problem. The linear function ฦ’(๐“) = 3 - ๐“ is given, and we are tasked to determine whether its area function (integral) is increasing or decreasing on the interval [0, 3]. The area function represents the accumulated area under the curve of ฦ’(๐“) starting from the left endpoint 0.
Step 2: Recall the relationship between a function and its area function. The area function is the integral of ฦ’(๐“) with respect to ๐“. Mathematically, the area function A(๐“) is defined as: Ax=0f(x)dx. The derivative of the area function, A'(๐“), is equal to ฦ’(๐“).
Step 3: Analyze the behavior of ฦ’(๐“) on the interval [0, 3]. The function ฦ’(๐“) = 3 - ๐“ is linear with a negative slope (-1), meaning it decreases as ๐“ increases. Specifically, ฦ’(๐“) starts at 3 when ๐“ = 0 and decreases to 0 when ๐“ = 3.
Step 4: Determine the behavior of the area function A(๐“). Since A'(๐“) = ฦ’(๐“), the area function A(๐“) increases wherever ฦ’(๐“) is positive. On the interval [0, 3], ฦ’(๐“) is positive (above the x-axis), so the area function A(๐“) is increasing throughout this interval.
Step 5: Visualize the problem. Draw the graph of ฦ’(๐“) = 3 - ๐“, which is a straight line decreasing from (0, 3) to (3, 0). Shade the area under the curve from ๐“ = 0 to a variable endpoint ๐“. As ๐“ moves from 0 to 3, the shaded area grows, confirming that the area function A(๐“) is increasing on [0, 3].

๋น„์Šทํ•œ ๋ฌธ์ œ์— ๋Œ€ํ•œ ๊ฒ€์ฆ๋œ ์˜์ƒ ๋‹ต๋ณ€:

์ด ์˜์ƒ ํ•ด๋ฒ•์€ ์œ„ ๋ฌธ์ œ์— ๋„์›€์ด ๋œ๋‹ค๊ณ  ํŠœํ„ฐ๋“ค์ด ์ถ”์ฒœํ•œ ๊ฒƒ์ž…๋‹ˆ๋‹ค.
์˜์ƒ ๊ธธ์ด:
3m
๋„์›€์ด ๋˜์—ˆ๋‚˜์š”?

์ฃผ์š” ๊ฐœ๋…

์งˆ๋ฌธ์— ์˜ฌ๋ฐ”๋ฅด๊ฒŒ ๋‹ตํ•˜๊ธฐ ์œ„ํ•ด ๋ฐ˜๋“œ์‹œ ์ดํ•ดํ•ด์•ผ ํ•˜๋Š” ํ•ต์‹ฌ ๊ฐœ๋…๋“ค์€ ๋‹ค์Œ๊ณผ ๊ฐ™์Šต๋‹ˆ๋‹ค.

Decreasing Functions

A function is considered decreasing on an interval if, for any two points x1 and x2 within that interval, where x1 < x2, the function value at x1 is greater than the function value at x2 (ฦ’(x1) > ฦ’(x2)). In this case, the linear function ฦ’(๐“) = 3 - ๐“ decreases as x increases, indicating that as we move from 0 to 3, the output values of the function get smaller.
์ถ”์ฒœ ์˜์ƒ:
07:32
Determining Where a Function is Increasing & Decreasing

Area Function

The area function A(x) associated with a function ฦ’(๐“) represents the accumulated area under the curve of ฦ’ from a starting point (in this case, 0) to a variable endpoint x. Mathematically, it is defined as A(x) = โˆซ[0,x] ฦ’(t) dt. The behavior of the area function depends on the values of the original function; if ฦ’ is decreasing, the area function will reflect this change.
์ถ”์ฒœ ์˜์ƒ:
05:06
Finding Area When Bounds Are Not Given

Relationship Between Function and Area Function

The relationship between a function and its area function is governed by the Fundamental Theorem of Calculus. If the original function is decreasing, the area function will increase at a decreasing rate. This means that while the area function A(x) is increasing as x moves from 0 to 3, the rate of increase diminishes because the heights of the rectangles (representing area) are getting smaller as the function value decreases.
์ถ”์ฒœ ์˜์ƒ:
05:23
Finding Area Between Curves on a Given Interval
๊ด€๋ จ ์‹ค์ฒœ
๊ต๊ณผ์„œ ์งˆ๋ฌธ

Definite integrals Use geometry (not Riemann sums) to evaluate the following definite integrals. Sketch a graph of the integrand, show the region in question, and interpret your result.                                                                                                                                      

                                                                                                                                                                                       

 โˆซโ‚€โด (8โ€•2๐“) d๐“

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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Definite integrals Evaluate the following integrals using the Fundamental Theorem of Calculus


โˆซโ‚โธ 8๐“ยน/ยณ d๐“

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Average distance on a parabola What is the average distance between the parabola y = 30๐“ (20 โ€• ๐“ ) and the ๐“-axis on the interval [0, 20] ?

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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Definite integrals Evaluate the following integrals using the Fundamental Theorem of Calculus. Explain why your result is consistent with the figure.


โˆซโ‚€ยน (๐“ยฒ โ€• 2๐“ + 3) d๐“


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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Definite integrals Evaluate the following integrals using the Fundamental Theorem of Calculus


โˆซโ‚‹โ‚‚โปยน ๐“โปยณ d๐“

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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Explain why or why not Determine whether the following statements are true and give an explanation or counterexample. Assume ฦ’ and ฦ’' are continuous functions for all real numbers.

(d) If ฦ’ is continuous on [a,b] and โˆซโ‚แต‡ |ฦ’(๐“)| d๐“ = 0 , then ฦ’(๐“) = 0 on [a,b] .

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