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Ch. 5 - Integration
5์žฅ, ๋ฌธ์ œ 5.4.5

Use symmetry to explain why.
โˆซโดโ‚‹โ‚„ (5๐“โด + 3๐“ยณ + 2๐“ยฒ + ๐“ + 1) d๐“ = 2 โˆซโ‚€โด (5๐“โด + 2๐“ยฒ + ๐“ + 1) d๐“ .

๊ฒ€์ฆ๋œ ๋‹จ๊ณ„๋ณ„ ์•ˆ๋‚ด
1
Step 1: Recognize that the integral is over a symmetric interval [-4, 4]. Symmetry in integrals often simplifies calculations, especially when the integrand has specific properties like even or odd functions.
Step 2: Break down the integrand into individual terms: 5๐“โด, 3๐“ยณ, 2๐“ยฒ, ๐“, and 1. Analyze each term to determine whether it is an even function or an odd function. Recall that even functions satisfy f(-๐“) = f(๐“), while odd functions satisfy f(-๐“) = -f(๐“).
Step 3: Identify the symmetry of each term: 5๐“โด and 2๐“ยฒ are even functions, while 3๐“ยณ and ๐“ are odd functions. The constant term 1 is also even because it does not depend on ๐“.
Step 4: Use the property of integrals over symmetric intervals: The integral of an odd function over [-a, a] is zero because the positive and negative contributions cancel out. Therefore, the terms 3๐“ยณ and ๐“ do not contribute to the integral over [-4, 4].
Step 5: Rewrite the original integral by excluding the odd terms and focusing only on the even terms. This simplifies the integral to โˆซโดโ‚‹โ‚„ (5๐“โด + 2๐“ยฒ + ๐“ + 1) d๐“ = 2 โˆซโ‚€โด (5๐“โด + 2๐“ยฒ + ๐“ + 1) d๐“, leveraging the symmetry of the even functions over the interval.

๋น„์Šทํ•œ ๋ฌธ์ œ์— ๋Œ€ํ•œ ๊ฒ€์ฆ๋œ ์˜์ƒ ๋‹ต๋ณ€:

์ด ์˜์ƒ ํ•ด๋ฒ•์€ ์œ„ ๋ฌธ์ œ์— ๋„์›€์ด ๋œ๋‹ค๊ณ  ํŠœํ„ฐ๋“ค์ด ์ถ”์ฒœํ•œ ๊ฒƒ์ž…๋‹ˆ๋‹ค.
์˜์ƒ ๊ธธ์ด:
3m
๋„์›€์ด ๋˜์—ˆ๋‚˜์š”?

์ฃผ์š” ๊ฐœ๋…

์งˆ๋ฌธ์— ์˜ฌ๋ฐ”๋ฅด๊ฒŒ ๋‹ตํ•˜๊ธฐ ์œ„ํ•ด ๋ฐ˜๋“œ์‹œ ์ดํ•ดํ•ด์•ผ ํ•˜๋Š” ํ•ต์‹ฌ ๊ฐœ๋…๋“ค์€ ๋‹ค์Œ๊ณผ ๊ฐ™์Šต๋‹ˆ๋‹ค.

Symmetry in Functions

Symmetry in functions refers to the property where a function exhibits identical behavior on either side of a central point, typically the y-axis for even functions or the origin for odd functions. For example, a function f(x) is even if f(-x) = f(x), and odd if f(-x) = -f(x). This property can simplify the evaluation of integrals, particularly over symmetric intervals.
์ถ”์ฒœ ์˜์ƒ:
06:21
Properties of Functions

Definite Integrals

A definite integral calculates the net area under a curve defined by a function over a specific interval [a, b]. It is represented as โˆซ_a^b f(x) dx and provides a numerical value that represents this area. Understanding how to manipulate definite integrals, especially with respect to symmetry, is crucial for simplifying calculations.
์ถ”์ฒœ ์˜์ƒ:
05:43
Definition of the Definite Integral

Properties of Integrals

Properties of integrals include various rules that allow for the manipulation and evaluation of integrals. One important property is that the integral of an even function over a symmetric interval [-a, a] can be expressed as twice the integral from 0 to a. This property is essential for simplifying integrals involving symmetric functions, as seen in the given equation.
์ถ”์ฒœ ์˜์ƒ:
06:21
Properties of Functions
๊ด€๋ จ ์‹ค์ฒœ
๊ต๊ณผ์„œ ์งˆ๋ฌธ

Evaluate โˆซโ‚€ยฒ 3๐“ยฒ d๐“ and โˆซโ‚‹โ‚‚ยฒ 3๐“ยฒ d๐“. 

110
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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Indefinite integrals Use a change of variables or Table 5.6 to evaluate the following indefinite integrals. Check your work by differentiating.                                                                                  

                                                                                                                                                                    

 โˆซ 2 / (๐“โˆš4๐“ยฒ โ€•1) d๐“ , ๐“ > ยฝ 

61
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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Definite integrals Evaluate the following integrals using the Fundamental Theorem of Calculus


โˆซโ‚โด (๐“ โ€• 2)/โˆš๐“ d๐“

57
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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Indefinite integrals Use a change of variables or Table 5.6 to evaluate the following indefinite integrals. Check your work by differentiating.                                                                                  

                                                                                                                                                                    

 โˆซ ๐“ csc ๐“ยฒ cot ๐“ยฒ d๐“

71
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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Area by geometry Use geometry to evaluate the following integrals.


โˆซโดโ‚‹โ‚† โˆš(24 โ€• 2๐“ โ€• ๐“ยฒ) d๐“

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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Integrals with sinยฒ ๐“ and cosยฒ ๐“ Evaluate the following integrals.                                                                                                             

                                                                                                                                                                    

 โˆซโ‚‹ฯ€^ฯ€ cosยฒ ๐“ d๐“

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