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Ch. 7 - Logarithmic, Exponential Functions, and Hyperbolic Functions
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
7장, 문제 7.3.112b

Definitions of hyperbolic sine and cosine Complete the following steps to prove that when the x- and y-coordinates of a point on the hyperbola x² - y² = 1 are defined as cosh t and sinh t, respectively, where t is twice the area of the shaded region in the figure, x and y can be expressed as
x = cosh t = (eᵗ + e⁻ᵗ) / 2 and y = sinh t = (eᵗ - e⁻ᵗ) / 2.


Graph of hyperbola x² - y² = 1 with shaded area and point P(x, y) = (cosh t, sinh t) illustrating t as twice the area.


b. In Chapter 8, the formula for the integral in part (a) is derived:
∫ √(z² − 1) dz = (z/2)√(z² − 1) − (1/2) ln|z + √(z² − 1)| + C.
Evaluate this integral on the interval [1, x], explain why the absolute value can be dropped, and combine the result with part (a) to show that:
t = ln(x + √(x² − 1)).

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1
Start by expressing the parameter \( t \) as twice the shaded area, which is given by the formula: \[ t = 2 \left( \frac{1}{2} x y - \int_1^x \sqrt{z^2 - 1} \, dz \right) \]. This represents the area of the triangle minus the area under the curve from 1 to \( x \).
Recognize that the point \( P(x, y) \) lies on the hyperbola \( x^2 - y^2 = 1 \), and the coordinates are defined as \( x = \cosh t \) and \( y = \sinh t \). This means \( y = \sqrt{x^2 - 1} \) because \( y^2 = x^2 - 1 \).
Use the integral formula provided: \[ \int \sqrt{z^2 - 1} \, dz = \frac{z}{2} \sqrt{z^2 - 1} - \frac{1}{2} \ln|z + \sqrt{z^2 - 1}| + C \]. Evaluate this definite integral from 1 to \( x \) by substituting the limits into the antiderivative.
Explain why the absolute value in the logarithm can be dropped: since \( x \geq 1 \) and \( \sqrt{x^2 - 1} \geq 0 \), the expression inside the logarithm, \( x + \sqrt{x^2 - 1} \), is always positive, so \( |x + \sqrt{x^2 - 1}| = x + \sqrt{x^2 - 1} \).
Combine the evaluated integral with the expression for \( t \) from step 1, simplify the terms, and show that \( t = \ln(x + \sqrt{x^2 - 1}) \). This links the parameter \( t \) to the coordinates on the hyperbola and completes the proof.

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Hyperbolic Functions (sinh and cosh)

Hyperbolic sine (sinh) and cosine (cosh) are analogs of the trigonometric sine and cosine but for a hyperbola. They are defined as sinh t = (e^t - e^(-t))/2 and cosh t = (e^t + e^(-t))/2. These functions satisfy the identity cosh² t - sinh² t = 1, which corresponds to the equation of the hyperbola x² - y² = 1.
추천 영상:
가이드 코스
5:50
Asymptotes of Hyperbolas

Area Interpretation and Parametrization of the Hyperbola

The parameter t is defined as twice the area of the shaded region bounded by the hyperbola, the x-axis, and the vertical line at x. This geometric interpretation links the hyperbolic functions to the integral of √(z² - 1), providing a way to parametrize points on the hyperbola as (cosh t, sinh t).
추천 영상:
08:02
Parameterizing Equations

Integral of √(z² - 1) and Logarithmic Expression

The integral ∫√(z² - 1) dz evaluates to (z/2)√(z² - 1) - (1/2) ln|z + √(z² - 1)| + C. Evaluating this from 1 to x and dropping the absolute value (since x ≥ 1) leads to the expression t = ln(x + √(x² - 1)), connecting the parameter t to x and thus to cosh t.
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Logarithms Introduction
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