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Ch. 8 - Integration Techniques
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
8장, 문제 8.8.67b

66–71. {Use of Tech} Estimating error Refer to Theorem 8.1 in the following exercises.
67. Let f(x) = √(x³ + 1).
b. Calculate f''(x).

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Step 1: Recall the function f(x) = √(x³ + 1). To calculate f''(x), we first need to find f'(x), the first derivative of f(x). Use the chain rule for differentiation since f(x) involves a composition of functions.
Step 2: Start by differentiating the outer function √(u), where u = x³ + 1. The derivative of √(u) is (1 / (2√(u))) * du/dx. Substitute u = x³ + 1 into this formula.
Step 3: Differentiate the inner function x³ + 1 with respect to x. The derivative of x³ is 3x², and the derivative of 1 is 0. Therefore, du/dx = 3x².
Step 4: Combine the results from Step 2 and Step 3 to find f'(x). Substitute du/dx = 3x² into the formula for the derivative of √(u). This gives f'(x) = (1 / (2√(x³ + 1))) * 3x².
Step 5: To find f''(x), differentiate f'(x) = (3x² / (2√(x³ + 1))) using the quotient rule. The quotient rule states that if h(x) = g(x) / k(x), then h'(x) = (g'(x)k(x) - g(x)k'(x)) / [k(x)]². Apply this rule carefully to f'(x), treating the numerator and denominator separately.

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