74. Volume of a Solid
Consider the region R bounded by:
The graph of f(x) = 1/(x + 2)
The x-axis on the interval [0,3].
Find the volume of the solid formed when R is revolved about the y-axis.

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Step 1: Recognize that the problem involves finding the volume of a solid of revolution. Since the region R is revolved about the y-axis, we will use the method of cylindrical shells.

Step 2: Recall the formula for the volume of a solid using the method of cylindrical shells:

V = 2 π ∫

_a^b x f(x) dx, where x is the radius of the shell, f(x) is the height of the shell, and [a, b] is the interval of integration.

Step 3: Substitute the given function f(x) = 1/(x + 2) and the interval [0, 3] into the formula. The volume becomes:

V = 2 π ∫

₀³ x ∕ (x + 2) dx.

Step 4: Simplify the integrand

x ∕ (x + 2)

. Perform polynomial long division or rewrite the fraction to make it easier to integrate. This step will involve algebraic manipulation.

Step 5: Integrate the simplified expression with respect to x over the interval [0, 3]. After finding the antiderivative, evaluate it at the bounds 3 and 0, and multiply the result by 2π to find the volume.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Volume of Revolution

The volume of revolution refers to the volume of a solid formed by rotating a two-dimensional shape around an axis. In this case, the region R is rotated about the y-axis, which requires the use of integration techniques to calculate the volume. The method of cylindrical shells or the disk/washer method can be applied, depending on the axis of rotation and the function involved.

Integration

Integration is a fundamental concept in calculus that involves finding the accumulated area under a curve. In the context of finding volumes, integration allows us to sum up infinitesimally small cylindrical slices of the solid formed by the revolution. The definite integral will be evaluated over the specified interval to determine the total volume of the solid.

Function Behavior

Understanding the behavior of the function f(x) = 1/(x + 2) is crucial for this problem. This function is continuous and positive over the interval [0, 3], which means the region R is well-defined for the volume calculation. Analyzing the function's properties, such as its limits and shape, helps in visualizing the solid formed and ensures accurate integration.

74. Volume of a SolidConsider the region R bounded by:The graph of f(x) = 1/(x + 2)The x-axis on the interval [0,3].Find the volume of the solid formed when R is revolved about the y-axis.