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Ch.12 - Parametric and Polar Curves
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
12장, 문제 12.R.68

65–68. Eccentricity-directrix approach Find an equation of the following curves, assuming the center is at the origin. Graph the curve, labeling vertices, foci, asymptotes (if they exist), and directrices.
A hyperbola with vertices (±4, 0) and directrices x = ±2

검증된 단계별 안내
1
Identify the type of conic: Since the problem states it is a hyperbola with vertices at (±4, 0), the transverse axis is along the x-axis, and the center is at the origin (0,0).
Recall the standard form of a hyperbola centered at the origin with a horizontal transverse axis: \(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\), where \(a\) is the distance from the center to each vertex.
From the vertices (±4, 0), determine \(a = 4\), so \(a^2 = 16\).
Use the eccentricity-directrix relationship for a hyperbola: The directrices are given by \(x = \pm \frac{a}{e}\), where \(e\) is the eccentricity. Given the directrices at \(x = \pm 2\), set \(2 = \frac{a}{e}\) and solve for \(e\).
Recall the relationship between \(a\), \(b\), and \(e\) for a hyperbola: \(e = \frac{c}{a}\), where \(c^2 = a^2 + b^2\). Use the value of \(e\) found to express \(b^2\) in terms of \(a^2\) and \(e\), then write the full equation of the hyperbola.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
4m

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Definition of a Hyperbola Using Eccentricity and Directrix

A hyperbola can be defined as the set of points where the ratio of the distance to a focus and the distance to a corresponding directrix is a constant called eccentricity (e > 1). This eccentricity-directrix definition helps derive the equation of the hyperbola when the directrices and vertices are known.
추천 영상:
가이드 코스
05:43
Definition of the Definite Integral

Relationship Between Vertices, Foci, and Eccentricity

Vertices are points on the hyperbola closest to the center, and foci lie along the transverse axis beyond the vertices. The distance from the center to a vertex is 'a', to a focus is 'c', and eccentricity is defined as e = c/a. Knowing vertices and directrices allows calculation of 'a', 'c', and 'e' to find the hyperbola's equation.
추천 영상:
가이드 코스
5:22
Foci and Vertices of Hyperbolas

Standard Equation of a Hyperbola Centered at the Origin

For a hyperbola centered at the origin with a horizontal transverse axis, the standard form is (x²/a²) - (y²/b²) = 1. Here, 'a' is the distance from the center to each vertex, and 'b' relates to the conjugate axis. Using eccentricity and the relationship c² = a² + b², one can find 'b' and write the full equation.
추천 영상:
가이드 코스
5:59
Graph Hyperbolas NOT at the Origin