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Ch. 10 - Infinite Sequences and Series
Hass - Thomas' Calculus 15th Edition
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10장, 문제 10.4.74b

b. From Example 5, Section 10.2, show that
S = 1 + ∑(from n=1 to ∞) [1 / (n²(n + 1))].

검증된 단계별 안내
1
Recall the series expression from Example 5, Section 10.2, which involves the sum of terms related to \( \frac{1}{n^2 (n+1)} \). Our goal is to express \( S \) as \( 1 + \sum_{n=1}^\infty \frac{1}{n^2 (n+1)} \).
Start by writing the general term of the series: \( \frac{1}{n^2 (n+1)} \). To simplify or analyze this term, consider using partial fraction decomposition to break it into simpler fractions that are easier to sum.
Set up the partial fraction decomposition for \( \frac{1}{n^2 (n+1)} \) as \( \frac{A}{n} + \frac{B}{n^2} + \frac{C}{n+1} \), and solve for constants \( A, B, C \) by multiplying both sides by \( n^2 (n+1) \) and equating coefficients.
Once the partial fractions are found, rewrite the sum \( \sum_{n=1}^\infty \frac{1}{n^2 (n+1)} \) as the sum of simpler series involving \( \sum \frac{1}{n} \), \( \sum \frac{1}{n^2} \), and \( \sum \frac{1}{n+1} \).
Recognize that the term \( 1 \) outside the summation corresponds to the initial term or a boundary condition from the original series, completing the expression \( S = 1 + \sum_{n=1}^\infty \frac{1}{n^2 (n+1)} \).

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