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Ch. 10 - Infinite Sequences and Series
Hass - Thomas' Calculus 15th Edition
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10장, 문제 10.4.17

Determining Convergence or Divergence
Which of the series in Exercises 17–56 converge, and which diverge? Use any method, and give reasons for your answers.
∑ (from n=1 to ∞) 1 / (2√n + ³√n)

검증된 단계별 안내
1
Identify the general term of the series: \(a_n = \frac{1}{2\sqrt{n} + \sqrt[3]{n}}\).
Analyze the behavior of the denominator for large \(n\). Since \(\sqrt{n} = n^{1/2}\) and \(\sqrt[3]{n} = n^{1/3}\), the term \(2\sqrt{n}\) grows faster than \(\sqrt[3]{n}\) as \(n\) increases.
Approximate the general term for large \(n\) by focusing on the dominant term in the denominator: \(a_n \approx \frac{1}{2n^{1/2}}\).
Compare the series to a known benchmark series, such as the \(p\)-series \(\sum \frac{1}{n^p}\), where convergence depends on \(p\). Here, the comparison is with \(\sum \frac{1}{n^{1/2}}\).
Recall that the \(p\)-series \(\sum \frac{1}{n^p}\) converges if and only if \(p > 1\). Since \(1/2 < 1\), the comparison series diverges, so by the Comparison Test, the original series also diverges.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Infinite Series and Convergence

An infinite series is the sum of infinitely many terms. Determining whether a series converges means checking if the sum approaches a finite limit as the number of terms grows indefinitely. If the sum does not approach a finite value, the series diverges.
추천 영상:
가이드 코스
06:52
Convergence of an Infinite Series

Comparison Test

The Comparison Test helps determine convergence by comparing the given series to a known benchmark series. If the terms of the given series are smaller than those of a convergent series, it also converges; if larger than a divergent series, it diverges. This test is useful when terms are positive and can be bounded.
추천 영상:
가이드 코스
09:25
Direct Comparison Test

Asymptotic Behavior of Terms

Analyzing the dominant behavior of terms for large n helps simplify complex expressions. For example, in 1/(2√n + ³√n), the term with the slower decay rate (smaller exponent) dominates. Understanding which term controls the behavior is key to applying convergence tests effectively.
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가이드 코스
5:50
Asymptotes of Hyperbolas