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Ch. 3 - Derivatives
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077당신이 사용하는 게 아니라요?교과서 변경
3장, 문제 3.6.76b

Suppose that the functions f and g and their derivatives with respect to x have the following values at x = 0 and x = 1.


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Find the derivatives with respect to x of the following combinations at the given value of x.


b. f(x)g³(x), x = 0

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1
Step 1: Recognize that the function to differentiate is f(x)g³(x). To find its derivative, use the product rule and the chain rule.
Step 2: Apply the product rule: If h(x) = f(x)g³(x), then h'(x) = f'(x)g³(x) + f(x) * d/dx[g³(x)].
Step 3: Use the chain rule to differentiate g³(x): d/dx[g³(x)] = 3g²(x)g'(x). Substitute this into the product rule.
Step 4: Substitute the values of f(x), g(x), f'(x), and g'(x) at x = 0 from the table into the derivative expression. Specifically, f(0) = 1, g(0) = 1, f'(0) = 5, and g'(0) = 1/3.
Step 5: Combine the terms from the product rule and chain rule to express the derivative at x = 0. Simplify the expression without calculating the final numerical value.

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이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
5m
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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Product Rule

The product rule is a fundamental differentiation rule used when finding the derivative of the product of two functions. If u(x) and v(x) are differentiable functions, the derivative of their product is given by (uv)' = u'v + uv'. This rule is essential for solving problems involving the derivative of a product, such as f(x)g³(x).
추천 영상:
05:18
The Product Rule

Chain Rule

The chain rule is used to differentiate composite functions. If a function y = g(u) and u = f(x), then the derivative dy/dx is found by multiplying the derivative of g with respect to u by the derivative of u with respect to x, or dy/dx = (dy/du) * (du/dx). This rule is crucial when dealing with functions raised to a power, like g³(x), where g(x) is a function of x.
추천 영상:
05:02
Intro to the Chain Rule

Substitution of Values

Substitution involves replacing variables with specific values to evaluate expressions or derivatives at particular points. In this problem, after applying the product and chain rules, substitute x = 0 into the derived expression using the given values for f(x), g(x), f'(x), and g'(x) to find the derivative at x = 0. This step is necessary to obtain the numerical result.
추천 영상:
04:27
Substitution With an Extra Variable