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Ch. 3 - Derivatives
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077당신이 사용하는 게 아니라요?교과서 변경
3장, 문제 3.3.62b

The Reciprocal Rule


b. Show that the Reciprocal Rule and the Derivative Product Rule together imply the Derivative Quotient Rule.

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Start by recalling the Reciprocal Rule, which states that if you have a function \( f(x) \), the derivative of its reciprocal \( \frac{1}{f(x)} \) is given by \( -\frac{f'(x)}{(f(x))^2} \).
Next, recall the Product Rule for derivatives, which states that if you have two functions \( u(x) \) and \( v(x) \), the derivative of their product \( u(x)v(x) \) is \( u'(x)v(x) + u(x)v'(x) \).
To derive the Quotient Rule, consider a function \( \frac{u(x)}{v(x)} \). This can be rewritten as \( u(x) \cdot \frac{1}{v(x)} \).
Apply the Product Rule to \( u(x) \cdot \frac{1}{v(x)} \). Let \( u(x) \) be the first function and \( \frac{1}{v(x)} \) be the second function. The derivative is \( u'(x) \cdot \frac{1}{v(x)} + u(x) \cdot \left(-\frac{v'(x)}{(v(x))^2}\right) \).
Simplify the expression from the previous step to obtain the Quotient Rule: \( \frac{u'(x)v(x) - u(x)v'(x)}{(v(x))^2} \). This shows how the Reciprocal Rule and the Product Rule together imply the Quotient Rule.

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주요 개념

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Reciprocal Rule

The Reciprocal Rule in calculus states that the derivative of the reciprocal of a function f(x), denoted as 1/f(x), is given by -f'(x)/[f(x)]^2. This rule is essential for understanding how changes in the reciprocal of a function relate to changes in the function itself, particularly when combined with other derivative rules.
추천 영상:
5:50
Power Rules

Derivative Product Rule

The Derivative Product Rule is a fundamental concept in calculus used to find the derivative of the product of two functions. If u(x) and v(x) are differentiable functions, the derivative of their product u(x)v(x) is given by u'(x)v(x) + u(x)v'(x). This rule is crucial for handling derivatives involving products of functions, which is often encountered in complex calculus problems.
추천 영상:
05:18
The Product Rule

Derivative Quotient Rule

The Derivative Quotient Rule provides a method for differentiating a quotient of two functions. If u(x) and v(x) are differentiable functions, the derivative of their quotient u(x)/v(x) is given by [u'(x)v(x) - u(x)v'(x)]/[v(x)]^2. Understanding this rule is vital for solving problems involving division of functions, and it can be derived using the Reciprocal Rule and the Product Rule.
추천 영상:
06:43
The Quotient Rule
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S = πrr² + .


b. How is dS/dt related to dh/dt if r is constant?

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[Technology Exercise] Exercises 31–34 give the position function s = f(t) of an object moving along the s-axis as a function of time t. Graph f together with the velocity function v(t) = ds/dt = f'(t) and the acceleration function a(t) = d²s/dt² = f''(t). Comment on the object’s behavior in relation to the signs and values of v and a. Include in your commentary such topics as the following:


b. When does it move to the left (down) or to the right (up)?


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b. When is the body moving forward? Backward?

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Theory and Examples


In Exercises 51–54,


b. Graph y = f(x) and y = f'(x) side by side using separate sets of coordinate axes, and answer the following questions.


y = x⁴/4

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Suppose that functions ƒ(x) and g(x) and their first derivatives have the following values at x = 0 and x = 1.


x ƒ(x) g(x) ƒ'(x) g'(x)

0 1 1 -3 1/2

1 3 5 1/2 -4


Find the first derivatives of the following combinations at the given value of x.


b. ƒ(x)g²(x), x = 0

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Recovering a function from its derivative


b. Repeat part (a), assuming that the graph starts at (−2, 0) instead of (−2, 3).

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